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poj2481树状数组解二维偏序
按区间r降序排列,r相同按照l升序排列,两个区间相同时特判一下即可 ...
分类:编程语言   时间:2018-12-06 22:22:02    阅读次数:336
POJ2481:Cows(树状数组)
Description Farmer John's cows have discovered that the clover growing along the ridge of the hill (which we can think of as a one-dimensional number ...
分类:编程语言   时间:2017-05-25 18:58:18    阅读次数:269
poj2481 Cows
Description Farmer John's cows have discovered that the clover growing along the ridge of the hill (which we can think of as a one-dimensional number ...
分类:其他好文   时间:2017-05-17 21:32:30    阅读次数:183
POJ2481 Cows
题解: 给出n个区间,求每个区间是多少个区间的真子集 按照x从小到大排序,若x相同,则按照y从大到小排序。 然后每次需要判断一下x和y相同的个数,减去就行了 代码: ...
分类:其他好文   时间:2016-09-25 06:14:39    阅读次数:129
POJ2481(树状数组:统计数字 出现个数)
CowsTime Limit:3000MSMemory Limit:65536KTotal Submissions:15405Accepted:5133DescriptionFarmer John's cows have discovered that the clover growing alon...
分类:编程语言   时间:2016-01-18 12:09:23    阅读次数:162
POJ2481:Cows(树状数组)
Description Farmer John's cows have discovered that the clover growing along the ridge of the hill (which we can think of as a one-dimensional number line) in his field is particularly good.  ...
分类:编程语言   时间:2015-06-23 21:41:15    阅读次数:155
poj2481 Cows
Description Farmer John's cows have discovered that the clover growing along the ridge of the hill (which we can think of as a one-dimensional number line) in his field is particularly good.  Fa...
分类:其他好文   时间:2015-06-03 21:43:24    阅读次数:119
poj 2481 Cows 树状数组解法,详细解析。
Farmer John's cows have discovered that the clover growing along the ridge of the hill (which we can think of as a one-dimensional number line) in his field is particularly good. Farmer John has N cows (we number the cows from 1 to N). Each of Farmer Joh...
分类:编程语言   时间:2015-02-06 09:41:36    阅读次数:201
poj2481 cows(线段树单点更新)
题目链接: huangjing 题目意思: 给出n头牛的活动区间,比如区间[SI,sj]和[EI,EJ],如果前面一个区间完全包含另外一个区间那么说明前一头牛比后一头牛强壮。 思路:根据区间的右区间数来建树,然后用sum[]来维护牛在这些右区间的头数。首先要根据牛的区间顺序进行排序,当然从左像右排序,那么后面进行查询比自己强的牛的时候那么就只用找右区间比自己大的就可以了。那么如何更新呢...
分类:其他好文   时间:2014-10-19 23:18:34    阅读次数:250
POJ2481 Cows 树状数组的简单应用
题意给了你N头牛,每头牛的强壮值是一个区间[s,e],如果第 i 头牛比第 j 头牛强壮那么必须满足 Si Ej - Sj; 为了满足这三个条件我们进行排序,先以e降序排为先决条件,若e相等则让s升序排列,如此即可满足三个条件,这道题目任意两头牛的强壮值区间有可能完全一样,这样就不需要重新用树状数组求一次和了,直接赋值即可,这样可以省很多时间,因为已经排序处理了,所以即便区间相等的  肯定就是...
分类:其他好文   时间:2014-04-29 13:26:21    阅读次数:323
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