Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeat...
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其他好文 时间:
2014-12-28 12:51:44
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139
理论计算机科学领域最顶级学术会议FOCS和STOC1IEEE Symposium on Foundations of Computer Science(FOCS):http://ieee-focs.org/2 STOC:The Annual ACM Symposium on Theory of Co...
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其他好文 时间:
2014-12-27 19:00:08
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284
Combination SumGiven a set of candidate numbers (C) and a target number (T), find all unique combinations inCwhere the candidate numbers sums toT.Thes...
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其他好文 时间:
2014-12-27 13:54:43
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115
Problem Description
As we know,the fzu AekdyCoin is famous of math,especially in the field of number theory.So,many people call him "the descendant of Chen Jingrun",which brings him a good reputati...
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其他好文 时间:
2014-12-25 23:41:56
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443
Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.
For example, given n = 3, a solution set is:
"((()))", "(()())", "(())()", "()(())", "()()()"
...
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其他好文 时间:
2014-12-25 20:40:36
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143
题目链接:http://codeforces.com/problemset/problem/496/B题目意思:给出 n 位数你,有两种操作:1、将每一位数字加一(当某一位 > 9 时只保存个位数) 2、循环右移(最右边那个数字去到第一位上)。问经过若个两种操作的组合后,得到的最小数值为多少。 .....
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其他好文 时间:
2014-12-23 00:15:39
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261
问题描述:
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in
C where the candidate numbers sums to T.
Each number in C may only be used once in the c...
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其他好文 时间:
2014-12-22 22:55:09
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218
题目链接:B. Secret CombinationYou got a box with a combination lock. The lock has a display showingndigits. There are two buttons on the box, each button ...
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其他好文 时间:
2014-12-18 22:16:01
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231
第四讲介绍了机器学习是否可行的问题。1. 从给定的资料D中,找出一个接近目标f的假设g是可行的。比如PLA。但是,找到的这个g能否用于D以外的地方,这就难说了。2. Hoeffding's inequality回答了g是否能用于D以外的问题: (1)In probability theory, H....
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其他好文 时间:
2014-12-18 20:27:01
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384
题目
Given a set of candidate numbers (C) and a target number (T), find all unique combinations
in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimi...
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其他好文 时间:
2014-12-17 16:26:21
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170