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POJ 1458 Common Subsequence(最长公共子序列问题)
Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 39128   Accepted: 15770 Description A subsequence of a given sequence is the given seque...
分类:其他好文   时间:2014-10-29 17:06:06    阅读次数:261
POJ 2533 Longest Ordered Subsequence(LIS)
H -LISTime Limit:2000MSMemory Limit:65536KB64bit IO Format:%I64d & %I64uSubmitStatusDescriptionA numeric sequence ofaiis ordered ifa1<a2< ... <aN. Let...
分类:其他好文   时间:2014-10-28 23:49:45    阅读次数:261
poj 1458 Common Subsequence
Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 39058   Accepted: 15739 Description A subsequence of a given sequence is the given seque...
分类:其他好文   时间:2014-10-22 14:43:21    阅读次数:271
Distinct Subsequences 解题报告
题目:给两个字符串S和T,判断T在S中出现的次数。 A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE" is a subsequence...
分类:其他好文   时间:2014-10-19 17:09:51    阅读次数:190
POJ 2533 Longest Ordered Subsequence(dp LIS)
Language: Default Longest Ordered Subsequence Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 33986   Accepted: 14892 Description A numeric sequence of a...
分类:其他好文   时间:2014-10-19 11:38:30    阅读次数:249
POJ 1458 Common Subsequence
题意:求LCS Sol:经典的 LCS。 if ( i==0  || j==0 )  dp [ i , j ] = 0 ; else if ( X[ i ] == Y [  j ] ) dp [ i-1 , j-1 ] + 1; else dp [ i, j ] = max  (  dp[ i - 1 , j ] , dp [ i ,  j-1 ] )  #include #i...
分类:其他好文   时间:2014-10-18 21:01:51    阅读次数:203
poj2533--Longest Ordered Subsequence(dp:最长上升子序列)
Longest Ordered Subsequence Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 33943   Accepted: 14871 Description A numeric sequence of ai is ordered if a1  a2  ...
分类:其他好文   时间:2014-10-16 19:38:32    阅读次数:209
hdu 1159(Common Subsequence)简单dp,求出最大的公共的字符数
Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 23923    Accepted Submission(s): 10567 Problem Description A sub...
分类:其他好文   时间:2014-10-16 18:39:22    阅读次数:231
hdu1423||hdu4512--LCIS--try
要学的 太多了.学到的 都是有用的 即便你不会在比赛中遇到这个类型的 但是开拓了你的思维这2题 都是LCIS-Longest Common Increase Subsequence我是在这边学习的 传送这篇写的很好.我觉得对于4512要好好理解下啊 我想了好久 太白痴了....注意下 数组的对称性1...
分类:其他好文   时间:2014-10-16 18:26:32    阅读次数:338
POJ3061 Subsequence(二分前缀和法+尺取法)
二分+前缀和法 满足条件的子序列长度在(0,n)之间,sum[x+i]-sum[i]为从从第i个元素开始序列长度为x的元素的和。前缀和可在O(n)的时间内统计 sum[i]的值。再用二分找出满足条件的最小的子序列长度。 #include #include #include #include #include #include #include #include #include #inclu...
分类:其他好文   时间:2014-10-15 00:09:19    阅读次数:251
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