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安卓下cocos2dx实现cpp部分在线更新
目前cocos2dx + lua的方式可以动态更新所有的脚本文件,但是却无法动态更新cpp部分的代码(这部分东西一般我们称之为底包),事实上采用同样的方案在android下也是可以实现动态更新的,只需要将java代码里加载libgame.so的代码稍微做些修改即可     static {         System.loadLibrary("game");     }   ...
分类:移动开发   时间:2014-05-10 09:22:31    阅读次数:531
HDOJ 3622 Bomb Game
二分距离2sat Bomb Game Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3382    Accepted Submission(s): 1161 Problem Description R...
分类:其他好文   时间:2014-05-10 09:18:11    阅读次数:318
[2013山东ACM省赛] Alice and Bob
Alice and Bob Time Limit: 1000MS Memory limit: 65536K 题目描述     Alice and Bob like playing games very much.Today, they introduce a new game.     There is a polynomial like this: (a0*x^(2^0)...
分类:其他好文   时间:2014-05-10 08:44:35    阅读次数:363
gameon.mozilla.org
gameon.mozilla.org
分类:其他好文   时间:2014-05-08 13:21:45    阅读次数:183
JAVA的RSS处理
一:什么是RSSRSS(really simple syndication) :网页内容聚合器。RSS的格式是XML。必须符合XML 1.0规范。RSS的作用:订阅BLOG,订阅新闻二:RSS的历史版本:http://blogs.law.harvard.edu/tech/rssVersionHist...
分类:编程语言   时间:2014-05-08 13:08:55    阅读次数:671
codechef The Ball And Cups题解
The Ball And Cups At the end of a busy day, The Chef and his assistants play a game together. The game is not just for fun but also used to decide who will have to clean the kitchen. The Chef...
分类:其他好文   时间:2014-05-07 07:41:32    阅读次数:448
优先队列+模拟-Fox and Number Game
大意:每个测试用例是一个数组。找出xi和xj,(xi>xj),做运算令xi=xi-xj。可以做若干组这样的运算,使得最后的数组和最小。输出此和。 分析:用优先队列,每次找出最大的和次大的,处理后再加入此队列。注意多个相同的xi这种情况!...
分类:其他好文   时间:2014-05-07 07:19:27    阅读次数:301
codechef Subtraction Game 1题解
Subtraction Game 1 Chef is playing a game on a sequence of N positive integers, say A1, A2, ... AN. The game is played as follows. If all the numbers are equal, the game ends.Otherwise Sele...
分类:其他好文   时间:2014-05-07 03:14:01    阅读次数:280
android Beam
Beaming NDEF Messages to Other Devices Android Beam allows simple peer-to-peer data exchange between two Android-powered devices. The application that wants to beam data to another device must be in ...
分类:移动开发   时间:2014-05-06 23:21:48    阅读次数:620
A Simple Problem
For a given positive integer n, please find the smallest positive integer x that we can find an integer y such that y^2 = n +x^2.   Input The first line is an integer T, which is the the...
分类:其他好文   时间:2014-05-06 19:21:10    阅读次数:290
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