You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you cl ...
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其他好文 时间:
2017-06-09 19:12:15
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145
题目: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can yo ...
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编程语言 时间:
2017-05-28 21:34:59
阅读次数:
140
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you cl ...
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其他好文 时间:
2017-05-28 15:30:28
阅读次数:
145
题目描写叙述: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways ca ...
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其他好文 时间:
2017-05-25 14:40:43
阅读次数:
162
public class Solution { /** * @param n: An integer * @return: An integer */ public int climbStairs(int n) { // write your code here if (n == 0 || n ==... ...
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其他好文 时间:
2017-05-25 10:03:35
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190
题目: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can yo ...
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其他好文 时间:
2017-05-07 22:00:42
阅读次数:
200
Climbing Worm Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 12116 Accepted Submission(s): 8149 ...
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其他好文 时间:
2017-04-30 12:40:01
阅读次数:
226
题目描写叙述: 初阶:有n层的台阶,一開始你站在第0层,每次能够爬两层或者一层。请问爬到第n层有多少种不同的方法? 进阶:假设每次能够爬两层。和倒退一层,同一个位置不能反复走,请问爬到第n层有多少种不同的方法? 解题思路: 初阶:一维动态规划。爬楼梯数目事实上是一个斐波拉契数列。 假定f[i] 表示 ...
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其他好文 时间:
2017-04-23 11:54:13
阅读次数:
128
题目如下: 思路: 当n=1,结果为1 当n=2,结果为2 当n=3,结果为3 当n=4,结果为7 易递推[n]=[n-1]+[n-2],是一个斐波纳切数列。 本题代码: ...
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其他好文 时间:
2017-04-04 00:36:09
阅读次数:
135
P1561 [USACO12JAN]爬山Mountain Climbing 题目描述 Farmer John has discovered that his cows produce higher quality milk when they are subject to strenuous exe ...
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其他好文 时间:
2017-03-28 16:19:59
阅读次数:
236