Description
It's Halloween! Farmer John is taking the cows to a costume party, but unfortunately he only has one costume. The costume fits precisely two cows with a length of S (1 ≤ S ≤ 1,000,000)....
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其他好文 时间:
2015-04-09 21:56:32
阅读次数:
141
Description
Farmer John recently bought a bookshelf for cow library, but the shelf is getting filled up quite quickly, and now the only available space is at the top.
Each of the N cows (1 ≤ N ≤ 20,...
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其他好文 时间:
2015-04-09 21:54:52
阅读次数:
153
1734: [Usaco2005 feb]Aggressive cows 愤怒的牛Time Limit:5 SecMemory Limit:64 MBSubmit:217Solved:175[Submit][Status][Discuss]DescriptionFarmer John has bui...
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其他好文 时间:
2015-04-09 17:15:47
阅读次数:
124
Backward Digit Sums
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 4807
Accepted: 2772
Description
FJ and his cows enjoy playing a mental game. They write...
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其他好文 时间:
2015-04-07 10:07:10
阅读次数:
118
G - Balanced Lineup
Time Limit:5000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u
Submit Status Practice POJ 3264
Description
For the daily milking, Farmer John's N cows (1 ≤ N ≤ 50,000...
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其他好文 时间:
2015-04-07 10:05:56
阅读次数:
139
Lost CowsTime Limit:1000MSMemory Limit:65536KTotal Submissions:9660Accepted:6219DescriptionN (2 2 # include 3 # include 4 # include 5 # include 6 # i....
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编程语言 时间:
2015-04-07 01:57:33
阅读次数:
204
题目大意: 说给你n个线段的,告诉你每个线段的起始点S_i,和终止点E_i, 问这n条线段里有多少线段是相互包含的,如果两个端点重合不算包含。解题思路: 用树状数组搞就可以了,这道题是star的变形题,star是让我们求出有多个星星在这个星星的左下角,而这道题是让我们求出有多少个星星在这个星星的.....
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编程语言 时间:
2015-04-06 21:44:29
阅读次数:
192
http://acm.hdu.edu.cn/showproblem.php?pid=4292
Problem Description
You, a part-time dining service worker in your college’s dining hall, are now confused with a new problem: serve as many pe...
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其他好文 时间:
2015-04-06 17:23:00
阅读次数:
168
Space Elevator
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 9042
Accepted: 4296
Description
The cows are going to space! They plan to achieve orbit by b...
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其他好文 时间:
2015-04-06 08:57:23
阅读次数:
147
链接: click here~~
题意:农夫 John 建造了一座很长的畜栏,它包括N (2
但是,John的C (2
【解题思路】其实就是给你n个坐标,让你选m个(m
类似的最大化最小值或者最小化最大值的问题,通常用二分搜索法可以很好解决,我们定义:C(d)=可以安排的牛的位置使得最近的两头牛的距离不小于d,那么问题就变成了求满足C(d)的最大的d,其实也就是说,C(d)=可...
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其他好文 时间:
2015-04-05 23:39:53
阅读次数:
383