Fibonacci
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 9769
Accepted: 6959
Description
In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = F...
分类:
其他好文 时间:
2014-12-29 15:23:38
阅读次数:
107
How many Fibs?
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 10748
Accepted: 3982
Description
Recall the definition of the Fibonacci numbers:
f1 := 1...
分类:
其他好文 时间:
2014-12-29 09:01:26
阅读次数:
155
题目1092:Fibonacci
时间限制:1 秒
内存限制:32 兆
特殊判题:否
提交:1576
解决:1158
题目描述:
The Fibonacci Numbers{0,1,1,2,3,5,8,13,21,34,55...} are defined by the recurrence:
F0=0 F1=1 Fn=...
分类:
其他好文 时间:
2014-12-29 01:23:53
阅读次数:
177
In Gradle we can assign a task to a group. Gradle uses the group for example in the output of $ gradle -t to output all the tasks of the same group to...
分类:
其他好文 时间:
2014-12-27 21:39:47
阅读次数:
193
from:http://oracle-base.com/articles/10g/utl_dbws-10g.phpIn a previous article I presented a method for Consuming Web Services using a basic SOAP implementation. This article provides similar function...
分类:
数据库 时间:
2014-12-19 19:11:47
阅读次数:
625
嗯,,,矩阵乘法最基础的题了。Program CODEVS1250;type arr=array[1..2,1..2] of longint;var T,n,mo:longint; a,b:arr;operator *(a,b:arr) c:arr;var i,j,k,sum:longint...
分类:
其他好文 时间:
2014-12-17 20:42:02
阅读次数:
121
题目链接:http://www.cnblogs.com/frog112111/archive/2013/05/19/3087648.htmlFibonacci数列:F(0)=1 , F(1)=1 , F(n)=F(n-1)+F(n-2)我们以前快速求Fibonacci数列第n项的方法是 构造常系数矩...
分类:
其他好文 时间:
2014-12-17 20:27:59
阅读次数:
150
题目来源:南阳OJhttp://acm.nyist.net/JudgeOnline/problem.php?pid=13Fibonacci数时间限制:3000ms | 内存限制:65535KB难度:1描述无穷数列1,1,2,3,5,8,13,21,34,55...称为Fibonacci数列,它可以递...
分类:
其他好文 时间:
2014-12-17 20:17:22
阅读次数:
177
Battle Ships is a new game which is similar to Star Craft. In this game, the enemy builds a defense tower, which has L longevity. The player has a military
factory, which can produce N kinds of batt...
分类:
其他好文 时间:
2014-12-15 23:40:22
阅读次数:
304
UVA10229Modular Fibonacci(矩阵快速幂)
题目链接
题目大意:给你i和m,求Mi, Mi = (F(i - 1) + F(i - 2)) % 2^m;
解题思路:因为Mi = (F(i - 1) % 2^m + F(i - 2)% 2^m) % 2^m = (M(i - 1) + M(i - 2)) % 2^m.类似于求fibonacci数加上取模,只是n...
分类:
其他好文 时间:
2014-12-13 12:17:08
阅读次数:
150