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poj 3070 Fibonacci
Fibonacci Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9769   Accepted: 6959 Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = F...
分类:其他好文   时间:2014-12-29 15:23:38    阅读次数:107
poj 2413 How many Fibs?
How many Fibs? Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10748   Accepted: 3982 Description Recall the definition of the Fibonacci numbers:  f1 := 1...
分类:其他好文   时间:2014-12-29 09:01:26    阅读次数:155
九度OJ 1092 Fibonacci
题目1092:Fibonacci 时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:1576 解决:1158 题目描述:     The Fibonacci Numbers{0,1,1,2,3,5,8,13,21,34,55...} are defined by the recurrence:      F0=0 F1=1 Fn=...
分类:其他好文   时间:2014-12-29 01:23:53    阅读次数:177
Gradle Goodness: Group Similar Tasks
In Gradle we can assign a task to a group. Gradle uses the group for example in the output of $ gradle -t to output all the tasks of the same group to...
分类:其他好文   时间:2014-12-27 21:39:47    阅读次数:193
UTL_DBWS - Consuming Web Services in Oracle 10g Onward
from:http://oracle-base.com/articles/10g/utl_dbws-10g.phpIn a previous article I presented a method for Consuming Web Services using a basic SOAP implementation. This article provides similar function...
分类:数据库   时间:2014-12-19 19:11:47    阅读次数:625
CODEVS1533 Fibonacci数列 (矩阵乘法)
嗯,,,矩阵乘法最基础的题了。Program CODEVS1250;type arr=array[1..2,1..2] of longint;var T,n,mo:longint; a,b:arr;operator *(a,b:arr) c:arr;var i,j,k,sum:longint...
分类:其他好文   时间:2014-12-17 20:42:02    阅读次数:121
【转】 矩阵构造方法
题目链接:http://www.cnblogs.com/frog112111/archive/2013/05/19/3087648.htmlFibonacci数列:F(0)=1 , F(1)=1 , F(n)=F(n-1)+F(n-2)我们以前快速求Fibonacci数列第n项的方法是 构造常系数矩...
分类:其他好文   时间:2014-12-17 20:27:59    阅读次数:150
Fibonacci数列实验
题目来源:南阳OJhttp://acm.nyist.net/JudgeOnline/problem.php?pid=13Fibonacci数时间限制:3000ms | 内存限制:65535KB难度:1描述无穷数列1,1,2,3,5,8,13,21,34,55...称为Fibonacci数列,它可以递...
分类:其他好文   时间:2014-12-17 20:17:22    阅读次数:177
ZOJ3623:Battle Ships(完全背包)
Battle Ships is a new game which is similar to Star Craft. In this game, the enemy builds a defense tower, which has L longevity. The player has a military factory, which can produce N kinds of batt...
分类:其他好文   时间:2014-12-15 23:40:22    阅读次数:304
UVA10229Modular Fibonacci(矩阵快速幂)
UVA10229Modular Fibonacci(矩阵快速幂) 题目链接 题目大意:给你i和m,求Mi, Mi = (F(i - 1) + F(i - 2)) % 2^m; 解题思路:因为Mi = (F(i - 1) % 2^m + F(i - 2)% 2^m) % 2^m = (M(i - 1) + M(i - 2)) % 2^m.类似于求fibonacci数加上取模,只是n...
分类:其他好文   时间:2014-12-13 12:17:08    阅读次数:150
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