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Codeforces Round #304 (Div. 2)——Cdfs——Soldier and Cards
Two bored soldiers are playing card war. Their card deck consists of exactlyncards, numbered from1ton,all values are different. They divide cards betw...
分类:其他好文   时间:2015-05-26 20:43:23    阅读次数:141
杭电acm Identity Card
题目链接:http://acm.hdu.edu.cn/game/entry/problem/show.php?chapterid=1&sectionid=2&problemid=25好的吧,不得不说我因为一个Hone Kong卡了好几个小时,改来改去,使用了几种方式:1,使用hashmap保存所有的...
分类:其他好文   时间:2015-05-23 18:08:30    阅读次数:237
cf 546C Soldier and Cards
题目链接:C. Soldier and CardsTwo bored soldiers are playing card war. Their card deck consists of exactlyncards, numbered from1ton,all values are differen...
分类:其他好文   时间:2015-05-23 11:19:37    阅读次数:134
安卓Handler和Looper的假想
if (Looper.myLooper() != Looper.getMainLooper()) {                 // If we finish marking off of the main thread, we need to                 // actually do it on the main thread to ensure correct o...
分类:移动开发   时间:2015-05-22 19:11:05    阅读次数:136
浅析Hibernate映射(二)——关系映射(3)
双向一对一关联映射与单向一对一关联映射一样,双向映射依然可以采用两种方式实现:1、主键关联;2、唯一外键关联1、主键关联映射出的关系模型与单向一样:映射文件与单向的区别在于:需要在Card加入标签,指示hibernate将关联对象User根据主键加载上来。不影响存储,只影响加载User.hbm.xm...
分类:Web程序   时间:2015-05-21 18:56:39    阅读次数:119
循环中不要放入openSession()
for(Shop s:list) { System.out.println(s.getName()); String sql="select shopId,sum(ele_bank+ele_card+water_card+water_bank+coal_c...
分类:其他好文   时间:2015-05-21 01:21:35    阅读次数:152
Java Card Applet开发:OO还是C-style?
近日又在重构PBOC 2.0的EDEP,按客户的需求改了几十个细节。改动过程中对面向对象的理解有点加深。例如为了避免两个class相互依赖,可以用一个Interface居中作为解耦。由于卡内空间有限,资源紧缺,在设计时应注意避免继承层次过深。个人感觉,由于资源有限,不大可能大量应用各种设计模式。JA...
分类:移动开发   时间:2015-05-18 10:35:10    阅读次数:168
LightOJ1364---Expected Cards(概率dp+三进制状压)
Taha has got a standard deck of cards with him. In addition to the 52 regular ones, there are 2 joker cards. Every regular card has a rank and a suit. The ranks in ascending order are: A, 2, 3, 4, 5, 6...
分类:其他好文   时间:2015-05-18 09:10:39    阅读次数:163
poj 1651 区间dp
Multiplication Puzzle Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one card out of the row and scores the number of points equal to the product of the number o...
分类:其他好文   时间:2015-05-17 12:18:43    阅读次数:88
CSUOJ1206--Card game
如果我们可以求出两个人n张牌取k张的所有情况,问题就会变成一个简单的排列问题:A获胜的概率=A k张牌比B k张牌大的情况/总情况.然后我们可以用dp处理出n张牌中取k张牌的所有情况,dp[i][j][k]表示前i张牌中取j张牌构成k点的情况数, 状态转移:dp[i][j][k]=dp[i-1][j][k]+k>=a[i]?dp[i-1][j-1][k-a[i]]:0; 然后就是在计算概率时因为...
分类:其他好文   时间:2015-05-16 23:24:30    阅读次数:230
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