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Leet Code OJ 235. Lowest Common Ancestor of a Binary Search Tree [Difficulty: Easy]
题目: Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined betwee...
分类:其他好文   时间:2016-03-07 15:06:42    阅读次数:148
Leet Code OJ 223. Rectangle Area [Difficulty: Easy]
题目: Find the total area covered by two rectilinear rectangles in a 2D plane.Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total ar...
分类:其他好文   时间:2016-03-07 14:00:20    阅读次数:292
vmware Unable to open kernel device "\\.\Global\vmx86": The system cannot find the file 的解决方法
https://communities.vmware.com/thread/245800?start=0&tstart=0 I have exactly same issue. I start CMD as administrator then run "net start vmx86". Prob
分类:系统相关   时间:2016-03-07 10:17:53    阅读次数:193
lintcode-easy-Single Number
Given 2*n + 1 numbers, every numbers occurs twice except one, find it. Given [1,2,2,1,3,4,3], return 4 因为所有数都出现了两次,只有一个出现一次,所以只要把所有数做XOR,就可以得到出现一次的数 p
分类:其他好文   时间:2016-03-07 07:50:19    阅读次数:202
LR接口测试
get请求代码: Action(){ //检查点 /* web_reg_find("Search=Body", "SaveCount=result", "Text=true", LAST); */ //关联 web_reg_save_param("result", "LB=result\":", "
分类:其他好文   时间:2016-03-07 07:48:31    阅读次数:271
4. Median of Two Sorted Arrays
There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity sh
分类:其他好文   时间:2016-03-07 01:21:12    阅读次数:136
UVA11987Almost Union-Find(并查集删除节点)
题目链接 题意:n个数(即1-n)和m个操作: 1表示把x和y合并,2表示把x移到y集合里面,3表示统计x集合的元素个数 1,3好说,关键是2操作,可以先把2删除掉,删除的操作可以找一个其他的数字来取代x,这样就有新生出来一个集合,移到y集合就合并 #include <iostream> #incl
分类:其他好文   时间:2016-03-07 01:17:46    阅读次数:213
LeetCode(313):Super Ugly Number
Super Ugly Number: Write a program to find the nth super ugly number.Super ugly numbers are positive numbers whose all prime factors are in the given ...
分类:其他好文   时间:2016-03-06 20:40:54    阅读次数:126
【ST】hw2——find the error in the follow case
public int findLast (int[] x, int y) { //Effects: If x==null throw NullPointerException // in x that equals y. // If no such element exists, return -1
分类:其他好文   时间:2016-03-06 17:31:02    阅读次数:127
318. Maximum Product of Word Lengths
Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assum
分类:其他好文   时间:2016-03-06 17:18:00    阅读次数:155
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