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MemSQL Start[c]UP 2.0 - Round 2 - Online Round
搞到凌晨4点一个没出,要gg了。A. Golden Systemhttp://codeforces.com/contest/458/problem/A 1 #include 2 #include 3 #include 4 #include 5 using namespace std; 6 const...
分类:数据库   时间:2014-08-11 11:41:42    阅读次数:285
[BestCoder Round #4] hdu 4931 Happy Three Friends
Happy Three Friends Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 70    Accepted Submission(s): 62 Problem Description   Dong-hao ...
分类:移动开发   时间:2014-08-11 10:15:23    阅读次数:295
[BestCoder Round #4] hdu 4932 Miaomiao's Geometry (贪心)
Miaomiao's Geometry Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 363    Accepted Submission(s): 92 Problem Description There...
分类:其他好文   时间:2014-08-11 10:09:02    阅读次数:321
BestCoder Round #4 Miaomiao's Geometry (暴力)
Problem Description There are N point on X-axis . Miaomiao would like to cover them ALL by using segments with same length. There are 2 limits: 1.A point is convered if there is a segments T , ...
分类:其他好文   时间:2014-08-11 02:56:41    阅读次数:229
Codeforces Round #260 (Div. 2)
A. Laptops题目意思: 给定n台电脑,第i台电脑的价格是ai ,质量是bi,问是否存在一台电脑价格比某台电脑价格底,但质量确比某台电脑的质量高,即是否存在ai bj?解题思路: 这题一定要看题目,a都是1~n的不同数,b也是1~n的不同数,此题只需要判断ai是否等于bi,如果ai!= b.....
分类:其他好文   时间:2014-08-11 00:05:51    阅读次数:273
BestCoder Round #4 1002
这题真是丧心病狂,引来今天的hack狂潮~Miaomiao's GeometryTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 10Accepte...
分类:其他好文   时间:2014-08-10 23:56:20    阅读次数:275
R语言基础
##数据获取x1=round(runif(100,min=80,max=100))x2=round(rnorm(100,mean=80, sd=7))x3=round(rnorm(100,mean=80,sd=18))x3[which(x3>100)]=100num=seq(2005138101,l...
分类:其他好文   时间:2014-08-10 23:53:50    阅读次数:260
BestCoder Round #4 之 Miaomiao's Geometry(2014/8/10)
Miaomiao's GeometryTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 10Accepted Submission(s): 3Pro....
分类:其他好文   时间:2014-08-10 21:31:00    阅读次数:373
Lesson 49-50 How to get promoted?
1 connection 联系,关系,连接部分,交通线 eg. Check all radiators for small leaks,especially round pipework connections.检查所有的暖气片,看有没有小裂缝,尤其是管道连接处附近。 eg. She used he...
分类:其他好文   时间:2014-08-10 12:56:20    阅读次数:396
计算一个正整数的阶乘(JavaScript)
function factorial(n) { if (isFinite(n) && n > 0 && n == Math.round(n)) { // 有限的正整数 if (!(n in factorial)) // 没有缓存结果 factorial[n] = n * factorial(n - ...
分类:编程语言   时间:2014-08-10 10:23:00    阅读次数:329
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