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1、高阶函数的介绍
高阶函数的英文名称是Higher Order Function,它们是以函数为参数的函数。主要用于映射(mapping)、过滤(filtering)、归档(folding)和排序(sorting)表。高阶函数让程序更具模块性,让函数更加通用。
函数sort具有2个参数,一个是需要排序的表,另一个是定序(Ordering)函数。下面展示了按...
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其他好文 时间:
2015-02-02 23:17:53
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440
判断一些字符串能首尾相连连在一起并查集求欧拉回路和通路Sample Input32acmibm3acmmalformmouse2okokSample OutputThe door cannot be opened.Ordering is possible.The door cannot be ope...
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其他好文 时间:
2015-02-01 21:42:23
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190
uva 10305 Ordering Tasks
John has n tasks to do. Unfortunately, the tasks are not independent and the execution of one task is only possible if other tasks have already been executed.
...
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其他好文 时间:
2015-02-01 13:33:21
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167
#define method 2
#if method == 0x00
#include
#include
/*
* struct array_cache
*
* Per cpu structures
* Purpose:
* - LIFO ordering, to hand out cache-warm objects from ...
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编程语言 时间:
2015-01-31 14:48:13
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276
参考网址:http://stackoverflow.com/questions/11541383/ordering-by-list-of-strings-in-oracle-sql-without-listagg字符串拼接技巧和方式:http://www.oracle-base.com/articl...
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其他好文 时间:
2015-01-30 17:27:20
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330
For ordering the bytes representing an object, there are two common conventions. Consider a w-bit integer having a bit representation [xw-1, xw-2, ... , x1, x0 ], where xw-1 is the most significant...
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其他好文 时间:
2015-01-28 13:09:28
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169
uva 140 Bandwidth
Given a graph (V,E) where V is a set of nodes and E is a set of arcs in VxV, and an
ordering on the elements in V, then the bandwidth of a node
v is defined as the maxim...
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其他好文 时间:
2015-01-28 09:51:07
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137
《Time, Clocks, and the?Ordering of Events in?a Distributed System》(分布式系统的时钟和事件顺序)是分布式领域非常重要的经典论文,由Leslie Lamport 在1978年发表。 我就这么简单理解:在分布式系统中,...
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其他好文 时间:
2015-01-27 15:13:14
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200
题意 输出n个数m组小于关系的一种可能的拓扑排序
应用dfs拓扑排序 访问j时 若存在i
#include
using namespace std;
const int N = 105;
int n, m, t, v[N], tpo[N], g[N][N];
void dfs(int j)
{
if(v[j]) return;
for(int i = 1; i <= ...
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编程语言 时间:
2015-01-23 16:26:31
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124
物理页面 /* * Try to keep the most commonly accessed fields in single cache lines * here (16 bytes or greater). This ordering should be particularly * b.....
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系统相关 时间:
2015-01-22 23:06:34
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208