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Could not find action or result: /SendMail/servlet/UploadServlet
1、错误描述八月 14, 2015 3:03:05 下午 com.opensymphony.xwork2.util.logging.jdk.JdkLogger warn 警告: Could not find action or result: /SendMail/servlet/UploadServlet There is no Action mapped for action name Uplo...
分类:其他好文   时间:2015-08-15 15:01:25    阅读次数:106
linux下编译C++程序无法链接Mysql的问题
1.添加mysql的头文件MYSQLINC = /usr/local/mysql/include或MYSQLINC = /usr/local/mysql2.添加mysql的依赖库#find / -name "libmysqlclient*" // 查找mysql lib的目录MYSQLLIB = -...
分类:数据库   时间:2015-08-15 14:42:34    阅读次数:469
LeetCode:Majority Element Ⅱ
Given an integer array of size n, find all elements that appear more than ? n/3 ? times. The algorithm should run in linear time and in O(1) space.解法一...
分类:其他好文   时间:2015-08-15 11:41:06    阅读次数:103
shell之helloword
shell之helloword cd /bin ls -l | find -name sh ls -l | find -namd bash ls -l | grep -r sh??sh其实是指向dash ?lrwxrwxrwx 1 root root?????? 4 2014-12-11 03:13 sh -> dash ls -l | grep -r bash...
分类:系统相关   时间:2015-08-15 10:29:43    阅读次数:181
HDU 1796 How many integers can you find (容斥定理 + 二进制)
How many integers can you find Time Limit: 12000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5493    Accepted Submission(s): 1567 Problem Descripti...
分类:其他好文   时间:2015-08-15 10:25:58    阅读次数:121
poj 2945 Find the Clones (map+string,hash思维)
Find the Clones Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 7498   Accepted: 2780 Description Doubleville, a small town in Texas, was attacked by the ali...
分类:其他好文   时间:2015-08-15 00:17:48    阅读次数:158
hdu 4370 0 or 1 (最短路)
hdu 4370 0 or 1Description Given a n*n matrix C ij (1<=i,j<=n),We want to find a n*n matrix X ij (1<=i,j<=n),which is 0 or 1.Besides,X ij meets the following conditions:1.X 12+X 13+…X 1n=1 2.X 1n+X 2...
分类:其他好文   时间:2015-08-14 22:49:26    阅读次数:190
HDU - 1599 find the mincost route(Floyd求最小环)
find the mincost route Time Limit: 2000MS Memory Limit: 32768KB 64bit IO Format: %I64d & %I64u Submit Status Description 杭州有N个景区,景区之间有一些双向的路来连接,现在8600想找一条旅...
分类:其他好文   时间:2015-08-14 22:47:38    阅读次数:120
Codeforces 19D(线段树+离散化)
题意:题意很好理解,三种操作: (1)add x y,添加坐标(x,y),(2)del x y,删除坐标(x,y),(3)find x y,找到并输出严格大于(x,y)的坐标里的最小坐标。 题解:因为点有200000个,而点坐标最大到1e9,所以要离散化处理,我们只需要对x离散化,然后每个x对应一个set存y,然后每次修改操作的时候,根据set内的值维护最大y。#include ...
分类:其他好文   时间:2015-08-14 21:36:26    阅读次数:258
Triangle LOVE
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 3574    Accepted Submission(s): 1401 Problem Description Recently, scientists find that...
分类:其他好文   时间:2015-08-14 21:34:01    阅读次数:229
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