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Android Non-UI to UI Thread Communications(Part 2 of 5)
Original:http://www.intertech.com/Blog/android-non-ui-to-ui-thread-communications-part-2-of-5/his isthe second part of my series of blog posts on Andr...
分类:移动开发   时间:2014-12-26 14:31:31    阅读次数:441
Partition List leetcode
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of...
分类:其他好文   时间:2014-12-25 22:10:27    阅读次数:180
Remove Duplicates from Sorted List II leetcode
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5. Given 1->1-...
分类:其他好文   时间:2014-12-24 21:32:51    阅读次数:214
ETL 解析
extract-transform-load (ETL)Everyone understands the three letters: You get the data out of its original source location (E), you do something to it (...
分类:其他好文   时间:2014-12-23 19:22:05    阅读次数:127
【Java 重难点知识】String s=new String("abc") 与 String="abc"; 区别
首先,Strings=newString("abc");这句话创建了2个对象;一个为new出来的一个实例对象,另一个则为"abc";s不为对象,s只是一个引用(C++中的指针)。查询Java中String类的构造器,有一个这样的构造器,api如下:public(original)初始化一个新创建的String对象,使其表示一个与参..
分类:编程语言   时间:2014-12-22 19:47:40    阅读次数:210
leetcode Remove Duplicates from Sorted List II
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving onlydistinctnumbers from the original list.For example,Given1->2->3-...
分类:其他好文   时间:2014-12-22 14:25:25    阅读次数:182
孤儿进程退出分析
详细解释linux进程find_new_reaper函数,forget_original_parent过程...
分类:系统相关   时间:2014-12-21 09:15:22    阅读次数:378
【LeetCode】Distinct Subsequences 解题报告
【题目】 Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which is formed from the original string by deleting some (...
分类:其他好文   时间:2014-12-18 12:03:46    阅读次数:118
程序员的困境
Original:Programmer’s Dilemma - I.M.H.O. - MediumTranslated by:cssmagicRecently I interviewed tens of candidates for a kernel programmer’s position. T...
分类:其他好文   时间:2014-12-16 09:56:56    阅读次数:257
UVA 1262 Password 暴力枚举
Password Time Limit: 3000ms Memory Limit: 131072KB This problem will be judged on UVA. Original ID: 1262 64-bit integer IO format: %lld      Java class name: Main Prev  Submit Status...
分类:其他好文   时间:2014-12-15 12:14:14    阅读次数:263
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