Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.
For example,
Given [0,1,0,2,1,0,1,3,2,1,2,1]...
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移动开发 时间:
2015-01-18 17:12:30
阅读次数:
165
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining....
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移动开发 时间:
2015-01-16 01:02:04
阅读次数:
202
首先,我们看一下官方文档中对Model的解释(或者说定义):Models are the heart of any JavaScript application, containing the interactive data as well as a large part of the logic surrounding it: conversions, validations, compute...
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Web程序 时间:
2015-01-15 14:21:19
阅读次数:
253
Implementint sqrt(int x).Compute and return the square root ofx.分析:二分查找。首先确定二分查找终止的条件和返回条件,其次对于与数字有关的题要注意int的表示范围防止溢出(比如该题两个int相乘可能会超过int的范围,故采用x/mid与...
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其他好文 时间:
2015-01-14 22:36:12
阅读次数:
221
Implementint sqrt(int x).Compute and return the square root ofx.参考:http://standalone.iteye.com/blog/1847368参考的是一个用二分查找实现的,这道题还可以用什么牛顿法之类的如果middle * mi...
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其他好文 时间:
2015-01-12 20:41:55
阅读次数:
122
Implement int sqrt(int x).
Compute and return the square root of x.
二分查找法:
class Solution {
public:
int sqrt(int x)
{
int high = INT_MAX;
int low = 0;
while(low...
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其他好文 时间:
2015-01-12 17:41:51
阅读次数:
138
Computing minimum volume bounding box is a hard problem in computer science. Exact algorithm costs O(n3) time complexity.However, for lots of applicat...
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其他好文 时间:
2015-01-08 10:58:58
阅读次数:
239
mahout(或者hadoop)优先使用用户指定的classpath加载jar包
问题:使用mahout0.8时,出现java.lang.NoSuchMethodError: org.apache.lucene.util.PriorityQueue
类似http://www.warski.org/blog/2013/10/using-amazons-elastic-map-reduce-to-compute-recommendations-with-apache-mahout-0-8/
原因:
$HADO...
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编程语言 时间:
2015-01-07 23:36:11
阅读次数:
297
1、启动openstack-nova-compute时提示找不到vmwareapi模块 【问题现象】 2015-01-07 12:17:43.445 5861 INFO nova.virt.driver [-] Loading compute driver ‘vmwareapi.VMwareVCDriver‘ 2015-01-07 12:17:43.449...
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其他好文 时间:
2015-01-07 22:17:03
阅读次数:
273
题目描述:
Implement int sqrt(int x).
Compute and return the square root of x.
思路分析:采用二分查找的思想。当未找到mid=x/mid时,若mid>x/mid,则表示mid-1为平方值最接近但不超过x的值,即结果为mid-1。若mid
代码:
if(x == 0 || x == 1)
...
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其他好文 时间:
2015-01-07 20:57:12
阅读次数:
143