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Substring with Concatenation of All Words
You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a concatenation of each word in L exactly once and without ...
分类:其他好文   时间:2015-01-29 14:41:06    阅读次数:91
POJ2337---Catenyms
Catenyms Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9887   Accepted: 2583 Description A catenym is a pair of words separated by a period such that the las...
分类:其他好文   时间:2015-01-29 14:37:51    阅读次数:133
逐字显示,并使用callback显示下一行
HTML结构: JS实现: /* lines words */ var w1 = '时光是琥珀', w2 = '泪一滴滴被反锁' w3='情书再不朽', w4='也磨成沙漏', w5='青春的上游', w6='白云飞走苍狗与海鸥', ...
分类:其他好文   时间:2015-01-29 12:46:37    阅读次数:179
转:六百字读懂Git
原文来自于:http://www.techug.com/git-in-600-words译注:来自 Hacker School 的 Mary Rose Cook 最近实现了一个纯 JavaScript 写就的 Git:Gitlet,包括了 Git 核心命令的概念实现。Mary 说,这个项目一是为了了...
分类:其他好文   时间:2015-01-29 11:51:40    阅读次数:169
[C++]LeetCode: 130 Word Ladder (BFS)
题目: Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a timeEach intermediate...
分类:编程语言   时间:2015-01-29 09:34:19    阅读次数:1950
欧拉计划(python) problem 17
Number letter counts Problem 17 If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total. If all the numbers ...
分类:编程语言   时间:2015-01-29 09:27:01    阅读次数:199
[LeetCode] Word Break 拆分词句
Given a stringsand a dictionary of wordsdict, determine ifscan be segmented into a space-separated sequence of one or more dictionary words.For exampl...
分类:其他好文   时间:2015-01-29 07:02:47    阅读次数:150
HDU 1247 Hat’s Words
题意:输入一些字符串,遍历这些字符串,如果它是由这些字符串中另外两个字符串组合而成,输出这个串。做法:将所有字符串插入Trie树中,然后分割字符串,遍历所有可能性。题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1247题目:Hat’s WordsTim...
分类:其他好文   时间:2015-01-28 23:44:37    阅读次数:262
UVa: 10391 - Compound Words
题目描述:给出一个词典,找出所有的复合词,即恰好有两个单词连接而成的单词。输入每行都是一个由小写字母组成的单词。输入已按照字典序从小到大排序,且不超过12000个单词。输出所有的复合词按照字典序从小到大排列。 思路:用set存储所有的单词,对于每个单词,遍历所有可能子单词组合,然后判断在set中是否都已经存储,若是则输出该单词。算法复杂度为O(n*lgn*|S|),其中|S|表示单词最大长度。 ...
分类:其他好文   时间:2015-01-28 14:44:22    阅读次数:131
SDRAM总结
使用的流程W9825G6JH winbond sdram 4M words X 4banks X 16bits=.Accesses to the SDRAM are burst oriented.Up to 200MHzCAS Latency 2 and 3Burst Length 1,2,4,9 ...
分类:其他好文   时间:2015-01-28 09:36:32    阅读次数:593
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