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USACO抓牛catchcow (bfs)
这题是黄巨大出的比赛题.http://poj.org/problem?id=3278DescriptionFarmer John has been informed of the location of a fugitive cow and wants to catch her immediatel...
分类:其他好文   时间:2014-06-19 00:58:53    阅读次数:510
PatentTips - Optimizing power usage by factoring processor architectural events to PMU
BACKGROUNDProcessor power consumption has become a major issue in recent years. The current trend of processor design to multi-core architecture as ea...
分类:其他好文   时间:2014-06-18 22:16:54    阅读次数:435
No suitable driver found for jdbc:mysql://localhost:3306/hibernate_basic
Struts Problem ReportStruts has detected an unhandled exception:Messages:No suitable driver found for jdbc:mysql://localhost:3306/hibernate_basicCanno...
分类:数据库   时间:2014-06-18 18:41:57    阅读次数:249
[fw]Real Mode addressing
Real Mode在 real mode 中,memory 的使用被限制在 1 MByte(220bytes) 內,可用的 address 範圍為 0x00000 ~ 0xFFFFF。由 memory address 的可用範圍可知,存取需要 20 bits 的長度,但在 8086 的 CPU 架構...
分类:其他好文   时间:2014-06-18 13:41:34    阅读次数:180
json
json1 在 JavaScript 中创建 JSON 对象 Name: Age: Address: Phone: json2 在 JavaScript 中创建 JSON 对象 ...
分类:Web程序   时间:2014-06-17 20:25:23    阅读次数:266
PatentTips - DMA address translation between peer-to-peer IO devices
BACKGROUNDAs processing resources have increased, demands to run multiple software programs and operating systems on a single microprocessor have also...
分类:其他好文   时间:2014-06-16 23:25:53    阅读次数:345
LeetCode - Restore IP Addresses
Given a string containing only digits, restore it by returning all possible valid IP address combinations. For example: Given "25525511135", return ["255.255.11.135", "255.255.111.35"]. (Order do...
分类:其他好文   时间:2014-06-16 19:24:42    阅读次数:248
NYOJ 483 Nightmare 【广搜】+【无标记】
Nightmare 时间限制:1000 ms  |  内存限制:65535 KB 难度:4 描述 Ignatius had a nightmare last night. He found himself in a labyrinth with a time bomb on him. The labyrinth has an exit, Ignatius should ...
分类:Web程序   时间:2014-06-16 18:57:52    阅读次数:268
Effective C++:条款20:宁以 pass-by-reference-to-const替换pass-by-value
(一) 调用函数的时候如果传递参数pass-by-value,那么函数参数都是以实际实参的副本为初值,调用端所获得的亦是函数返回值的一个复件。 看下面代码: class Person { public: Person(); virtual ~Person(); private: string name; string address; }; ...
分类:编程语言   时间:2014-06-16 14:57:30    阅读次数:184
HDU 1661 Assigments 贪心法题解
Problem Description In a factory, there are N workers to finish two types of tasks (A and B). Each type has N tasks. Each task of type A needs xi time to finish, and each task of type B needs yj ti...
分类:其他好文   时间:2014-06-15 11:26:42    阅读次数:195
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