码迷,mamicode.com
首页 >  
搜索关键字:compute    ( 1898个结果
POJ 2305 Basic remains(JAVA练习)
Description Given a base b and two non-negative base b integers p and m, compute p mod m and print the result as a base b integer. p mod m is defined as the smallest non-negative integer k such tha...
分类:编程语言   时间:2014-08-25 19:20:04    阅读次数:230
别以为真懂Openstack: 虚拟机创建的50个步骤和100个知识点(3)
四、Nova-compute步骤17:nova-compute接收到请求后,通过Resource Tracker将创建虚拟机所需要的资源声明占用步骤18:调用Neutron API配置Network,虚拟机处于Networking的状态需要注意的是,这一步虽然是配置Network,但是主要是数据结构...
分类:其他好文   时间:2014-08-23 22:49:41    阅读次数:500
Oracle表与索引的分析及索引重建
1.分析表与索引(analyze 不会重建索引)analyze table tablename compute statistics等同于 analyze table tablename compute statistics for table for all indexes for all col...
分类:数据库   时间:2014-08-23 16:43:11    阅读次数:247
compute Binomial Coefficient or combinations with dynamic programming
The ProblemWrite a function that takes two parameters n and k and returns the value of Binomial Coefficient C(n, k).For example, your function should ...
分类:其他好文   时间:2014-08-23 12:41:20    阅读次数:169
Linux checksum flag in kernel
net_device->feature| NETIF_F_NO_CSUM: No need to use L4 checksum, it used for loopback device.| NETIF_F_IP_CSUM: the device can compute L4 checksum in...
分类:系统相关   时间:2014-08-22 14:26:59    阅读次数:260
UVA - 10883 Supermean
Description Problem F Supermean Time Limit: 2 second "I have not failed. I've just found 10,000 ways that won't work." Thomas Edison Do you know how to compute the mean (or average...
分类:其他好文   时间:2014-08-20 21:11:33    阅读次数:378
扩展 OpenStack 的 REST API 的方法
以Nova REST API为例, 你应该按照以下步骤来扩展 Nova REST API (使用 类nova.api.openstack.compute.contrib.floating_ips.Floating_ips 作为例子)   1)    创建一个新的extension 子类. Extension子类应该派生于“nova.api.openstack.extensions Ext...
分类:Windows程序   时间:2014-08-19 19:09:35    阅读次数:349
UVA 10375 Choose and divide(数论)
The binomial coefficient C(m,n) is defined as m! C(m,n) = -------- n!(m-n)! Given four natural numbers p, q, r, and s, compute the the result of dividing C(p,q) by C(r,s). T...
分类:其他好文   时间:2014-08-18 23:37:43    阅读次数:274
POJ2785:4 Values whose Sum is 0(二分)
Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B x C x D are such that a + b + c + d = 0 . ...
分类:其他好文   时间:2014-08-18 18:43:52    阅读次数:210
Basic remains
Problem Description Given a base b and two non-negative base b integers p and m, compute p mod m and print the result as a base b integer. p mod m is defined as the smallest non-negative integer k ...
分类:其他好文   时间:2014-08-16 21:11:11    阅读次数:169
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!