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八步学SVN
This week I was attending a CI training course about svn. Here I‘d like to share what I have learnt. As I am an absolutely green bird to svn, this post only covers those most common usages. (1) C...
分类:其他好文   时间:2014-07-20 23:33:04    阅读次数:504
排队理论之性能分析 - Little Law & Utilization Law
了解一个系统的性能通常是参考一些度量值(Metric),而如何计算出这些Metric就是我们要讨论的。Little Law(排队理论:利特儿法则)和Utilization Law是Performance Engineering(System Engineering的一部分)常用的法则,它们都是数学理论,因此可作为性能计算的理论依据。详细分析两个法则超出了我个人的知识范围,因此我将仅仅谈一下如何应用...
分类:其他好文   时间:2014-07-20 10:25:28    阅读次数:290
One-Two-Three
Your little brother has just learnt to write one, two and three, in English. He has written a lot of those words in a paper, your task is to recognize...
分类:其他好文   时间:2014-07-19 11:30:29    阅读次数:225
Uva 12889 One-Two-Three
Your little brother has just learnt to write one, two and three, in English. He has written a lot of those words in a paper, your task is to recognize...
分类:其他好文   时间:2014-07-19 09:31:41    阅读次数:238
POJ2752 Seek the Name, Seek the Fame 【KMP】
Seek the Name, Seek the Fame Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11602   Accepted: 5680 Description The little cat is so famous, that many coup...
分类:其他好文   时间:2014-07-19 02:38:26    阅读次数:204
傻游戏停不下来:小鸟不在,伐木工来了
还记得年初那只傻鸟Flappy Bird吗?这个傻傻的游戏对移动游戏市场的影响,至今还未消散。...
分类:其他好文   时间:2014-07-17 19:09:10    阅读次数:191
Humming Bird A20 SPI2驱动编译
Humming Bird A20 SPI2编译使用 Yao.GUET 2014-07-17,转载请注明出处:http://blog.csdn.net/Yao_GUET A20上带有4个spi接口,由于Humming Bird A20只引出了SPI2,所以这里就以spi2为例,看一下fex文件是怎么设置的。 由于我拿到的linux内核上是已经有spi-sun7i的驱动代码文件,的民民主的所...
分类:其他好文   时间:2014-07-17 19:06:56    阅读次数:251
UVA - 536 Tree Recovery
Description   Tree Recovery  Little Valentine liked playing with binary trees very much. Her favorite game was constructing randomly looking binary trees with capital letters i...
分类:其他好文   时间:2014-07-17 17:21:38    阅读次数:253
使用OGEngine快速开发Flappy Bird
《flappybird》是由来自越南的独立游戏开发者DongNguyen所开发的作品,游戏中玩家必须控制一只小鸟,跨越由各种不同长度水管所组成的障碍,而这只鸟其实是根本不会飞的……所以玩家每点击一下小鸟就会飞高一点,不点击就会下降,玩家必须控制节奏,拿捏点击屏幕的时间点,让小..
分类:移动开发   时间:2014-07-17 16:15:11    阅读次数:267
NWERC 2011 ABCDEH 题解
A:SPOJ NWERC11A A - Binomial coefficients 题解:点击打开链接 B: 点击打开链接   Bird tree 从下到上发现是个gcd的过程(辗转相除 #include #include #include using namespace std; int main() { int T; scanf("%d", &T);...
分类:其他好文   时间:2014-07-15 13:07:18    阅读次数:317
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