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Unique Binary Search Trees II
Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.For example,Given n = 3, your program should return all ...
分类:其他好文   时间:2014-08-18 21:58:52    阅读次数:260
POJ 2318 计算几何+二分
TOYS Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10425 Accepted: 5002 Description Calculate the number of toys that land in each bin of a partitioned toy box. Mom and dad have a...
分类:其他好文   时间:2014-08-18 18:38:13    阅读次数:307
应用云存储瞄准企业级市场
就在外界都在猜测云存储厂商Dropbox和Box谁将先上市之际,3月25日,BOX率先公开向纽交所提交了上市申请。 此云存储非彼云存储 在分析这个新闻之前,我有必要做一个简单的澄清分析。长期以来,人们习惯把云存储等同于类似Dropbox之类的网盘服务,但是事实上,Dropbox不是标准意...
分类:其他好文   时间:2014-08-18 16:08:02    阅读次数:198
Validate Binary Search Tree
Given a binary tree, determine if it is a valid binary search tree (BST).Assume a BST is defined as follows:The left subtree of a node contains only n...
分类:其他好文   时间:2014-08-18 13:02:02    阅读次数:209
HTML解析
首先,新建一个工程,到Build Phases-link Binary With Libraries,点+添加libxml2运行库再到build settings中搜索Header search Paths,双击该选项第一行添加/usr/include/libxml2 此步骤为添加头文件把HTML....
分类:Web程序   时间:2014-08-18 09:14:43    阅读次数:292
Unique Binary Search Trees
Given n, how many structurally unique BST's (binary search trees) that store values 1...n?For example,Given n = 3, there are a total of 5 unique BST's...
分类:其他好文   时间:2014-08-18 00:03:13    阅读次数:189
Validate Binary Search Tree
Given a binary tree, determine if it is a valid binary search tree (BST).Assume a BST is defined as follows:The left subtree of a node contains only n...
分类:其他好文   时间:2014-08-17 21:11:02    阅读次数:213
Recover Binary Search Tree
Two elements of a binary search tree (BST) are swapped by mistake.Recover the tree without changing its structure.Note:A solution using O(n) space is ...
分类:其他好文   时间:2014-08-17 21:08:02    阅读次数:339
Ubuntu 14.04 上安装和配置 FTP 服务器 ProFTPD
proftpd的配置方式类似apache,比vsftpd更易用,xampp就集成了proftpd. apt-cache search proftpd 搜索相关包 sudo apt-get install proftpd-basic 安装 安装时默认作为一个standalone server运行proftpd,如果每天的...
分类:其他好文   时间:2014-08-17 18:43:02    阅读次数:296
组合模式解决原型创建对象传参和共享难题
//组合构造函数+原型模式function Box(name,age){ //保持独立的用构造函数 this.name = name; this.age = age; this.family = ['哥哥','姐姐','妹妹']};Box.prototype ...
分类:其他好文   时间:2014-08-17 18:18:02    阅读次数:175
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