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(*medium)LeetCode 233.Number of Digit One
Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n.For example:Given n = 13,Return 6...
分类:其他好文   时间:2015-08-04 20:58:01    阅读次数:110
跳过nextval查询当前序列值
原文地址——http://blog.csdn.net/qq525099302/article/details/47280211 user_sequences中保存着当前用户的所有序列信息,可以从这张系统内置表中查询当前序列值select seq.last_number from user_sequences seq where seq.sequence_name='SEQ_B_ORDER_ID';...
分类:其他好文   时间:2015-08-04 19:17:44    阅读次数:110
oracle 存储过程最好的记录错误方式
当你的应用有调用存储过程,而节点有几十个或者上百个,找错是不是一个很麻烦的事情,这个时候,我建议写到数据库中,下面是我做的一个demo. 1. 建立错误日志记录表 drop table PUB_PROC_ERR_LOG purge; create table PUB_PROC_ERR_LOG (   LOG_ID      NUMBER,   MODULE_NAME VARCHAR2(...
分类:数据库   时间:2015-08-04 19:11:01    阅读次数:184
leetcode——Count Complete Tree Nodes
题目Count Complete Tree Nodes Given a complete binary tree, count the number of nodes.In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last lev...
分类:其他好文   时间:2015-08-04 17:18:36    阅读次数:150
python基础学习小作业(一)
作业1:让用户输入数字,累加作业2:存10000块钱,年利率是3.25,多少年之后,存款能翻倍作业3:求用户输入数字的平均分作业1:#!/usr/bin/envpython #-*-coding:utf-8-*- x=0 whileTrue: num=raw_input(‘Pleaseinputnumber[Q/qtoexit]:‘) ifnum==‘q‘ornum==‘Q‘: print‘total..
分类:编程语言   时间:2015-08-04 16:01:27    阅读次数:326
[LeetCode] Gray Code
Gray Code The gray code is a binary numeral system where two successive values differ in only one bit. Given a non-negative integer n representing the total number of bits in the code, print t...
分类:其他好文   时间:2015-08-04 15:46:28    阅读次数:112
hdu 1164 Eddy's research I
Problem DescriptionEddy's interest is very extensive, recently he is interested in prime number. Eddy discover the all number owned can be divided int...
分类:其他好文   时间:2015-08-04 15:23:26    阅读次数:95
1069. The Black Hole of Numbers (20)
题目如下: For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obta...
分类:其他好文   时间:2015-08-04 13:34:40    阅读次数:134
LeetCode 191_Number of 1 Bits
两种思路: 思路一: 1、n&1 可得到最低位的数字,然后加到count变量中即可 2、n>>>1,注意是三个>不是两个>,三个的是逻辑移位,两个的是算术移位(Java中的定义) 缺点就是:有多少位就要需要移动多少次 思路二: 1、假设n= 1111000111000 那 n-1 = 1111000110111, (n-1) & n = 1111000110000,刚好把最...
分类:其他好文   时间:2015-08-04 13:33:58    阅读次数:101
HDU 1969 Pie(二分法)
My birthday is coming up and traditionally I’m serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes. F...
分类:其他好文   时间:2015-08-04 13:20:55    阅读次数:99
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