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decide your linux OS is GUI or not
Try: ps -ef|grep X The ps command will display information about a selection of the active processes (from the man page - man ps). This command will l ...
分类:系统相关   时间:2016-04-09 09:17:35    阅读次数:127
Two Strings Are Anagrams
Write a method anagram(s,t) to decide if two strings are anagrams or not. Example Given s="abcd", t="dcab", return true. 根据定义可知,两个字符串为anagrams,则每个字符出现 ...
分类:其他好文   时间:2016-04-04 22:36:53    阅读次数:135
Marvelous Mazes
Description Your mission, if you decide to accept it, is to create a maze drawing program. A maze will consist of the alphabetic characters A-Z, *(ast
分类:其他好文   时间:2016-03-18 21:35:11    阅读次数:265
lintcode-easy-Subtree
You have two every large binary trees: T1, with millions of nodes, and T2, with hundreds of nodes. Create an algorithm to decide if T2 is a subtree of
分类:其他好文   时间:2016-03-07 09:04:13    阅读次数:139
a decide for me
Today is 29 February,i have a decide that is i will take one hour to practice my english by writing sentence and reading in everyday from now on!So ab
分类:其他好文   时间:2016-02-29 02:02:12    阅读次数:161
【POJ 2484】A Funny Game
Description Alice and Bob decide to play a funny game. At the beginning of the game they pick n(1 <= n <= 10 6) coins in a circle, as Figure 1 shows.
分类:其他好文   时间:2016-02-06 01:44:21    阅读次数:189
poj 1704 Georgia and Bob(阶梯博弈)
Georgia and Bob Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 8656 Accepted: 2751 Description Georgia and Bob decide to play a self-inven
分类:其他好文   时间:2016-01-31 09:37:23    阅读次数:191
eden破解密文
题目名称破解密文题目描述题目大意:Mo and Larry have devised a way of encrypting messages. They first decide secretly on the number of columns and write the message (le...
分类:其他好文   时间:2015-12-09 13:51:02    阅读次数:180
工厂模式学习
Factory Method Design Pattern ??? 1.Intent ???????? <1> Define an interface for creating an object, but let subclasses decide which class to instantiate. Factory Method lets a cl...
分类:其他好文   时间:2015-11-13 17:11:25    阅读次数:348
判断同字幕异序词
Write a method to decide if two strings are anagrams or not解法:1 排序比较 (本次解法)2 判断每个字符出现的个数(直接)import java.util.Arrays;public class Anagrams { public ...
分类:其他好文   时间:2015-11-06 22:15:00    阅读次数:183
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