原文地址:http://blog.sina.com.cn/s/blog_7cd0c0a80100zmfe.html在android开发中LinearLayout很常用,LinearLayout的内控件的android:layout_weight在某些场景显得非常重要,比如我们需要按比例显示。andr...
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移动开发 时间:
2014-07-16 23:01:21
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296
activity-alias是android里为了反复使用Activity而设计的。当在Activity的onCreate()方法里,运行getIntent().getComponent().getClassName();得到的可能不是这个Activity的名字,有可能是别名的名字,比如:在Andr...
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其他好文 时间:
2014-07-16 20:48:56
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232
Follow up for "Unique Paths":Now consider if some obstacles are added to the grids. How many unique paths would there be?An obstacle and empty space i...
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其他好文 时间:
2014-07-16 18:09:43
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209
题目如下:
Don't Get Rooked
In chess, the rook is a piece that can move any number of squaresvertically or horizontally. In this problem we will consider smallchess boards (at most ...
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其他好文 时间:
2014-07-16 10:16:07
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254
Equations
Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5226 Accepted Submission(s): 2079
Problem Description
Consider equatio...
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其他好文 时间:
2014-07-16 10:10:58
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169
原文地址I’m a minimalist, and I don’t like to complicate software too early and unnecessarily. And adding components to a software system is one of the th...
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其他好文 时间:
2014-07-13 19:59:16
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480
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree and sum
...
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其他好文 时间:
2014-07-13 13:58:01
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184
Air Raid
Time Limit: 1000MS
Memory Limit: 10000K
Total Submissions: 6547
Accepted: 3896
Description
Consider a town where all the streets are one-way and each stree...
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其他好文 时间:
2014-07-12 21:04:44
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232
翻译之《Android Anatomy and Physiology》,下载地址:http://download.csdn.net/detail/wuxiaoer717/6839427大纲:1. Android剖析Linux内核本地库(Native Libraries)Android运行时(Andr...
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移动开发 时间:
2014-07-12 15:06:27
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340
LINUX环境下多线程编程肯定会遇到需要条件变量的情况,此时必然要使用pthread_cond_wait()函数。但这个函数的执行过程比较难于理解。
pthread_cond_wait()的工作流程如下(以MAN中的EXAMPLE为例):
Consider two shared variables x and y, protected by the mutex mut,...
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其他好文 时间:
2014-07-10 19:50:36
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347