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删除Checkout with Multiple Addresses
如果选择No,您的客户在结账时只可以输入一个收货地址,订单的货物都会送到这个地址。如果您选择Yes,您的客户将可以选择发货到多个地址,在购物车中的Proceed to Checkout按钮下面将会出现一个Checkout with Multiple Addresses的链接。为了使用这个结帐方式,您...
分类:其他好文   时间:2014-09-03 11:09:26    阅读次数:150
Method and apparatus for loading a segment register in a microprocessor capable of operating in multiple modes
A microprocessor contains an address generation unit, including a segment block, for loadingdescriptordata and a segment selector in a segment registe...
分类:移动开发   时间:2014-09-03 00:17:25    阅读次数:336
poj 1426 Find The Multiple
poj 1426 Find The Multiplehttp://poj.org/problem?id=1426题意:Given a positive integer n, write a program to find out a nonzero multiple(倍数) m of n whose...
分类:其他好文   时间:2014-09-02 19:51:15    阅读次数:186
python 学习笔记(4)
Expression in parentheses(), square bracket[], and curly braces{}can span multiple lines.A backslash (\) at the end of the line denotes continuation t...
分类:编程语言   时间:2014-09-02 05:51:34    阅读次数:238
UVa 11879 - Multiple of 17
题目:计算一个数是不是17的倍数。 说明:字符串,大数。简单题,直接判断即可。             设 n = 10a + d;(0 ≤ d ≤ 9)则             a - 5d = 51a - 5n,如果n被17整除,这个数必然也被17整除。 说明:题目给了个结论,不需要用,直接%17判断余数即可。 #include #include #include #incl...
分类:其他好文   时间:2014-09-01 10:49:03    阅读次数:143
Diamond-Problem
The_diamond_problem (钻石问题) http://en.wikipedia.org/wiki/Multiple_inheritance#The_diamond_problem The "diamond problem" (sometimes referred to as the "deadly diamond of death"[6]) is an ambigui...
分类:其他好文   时间:2014-08-30 15:13:50    阅读次数:232
LeetCode——Reverse Nodes in k-Group
Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is...
分类:其他好文   时间:2014-08-30 11:14:19    阅读次数:209
HDU 1019 Least Common Multiple
题解:求n个数的最小公倍数,一个一个算就可以了,需要注意的是LCM先除GCD再乘,因为先乘有可能会超范围,1WA的代价。#include int T,n,a,b;int gcd(int a,int b){if(b==0)return a;return gcd(b,a%b);}int main(){ ...
分类:其他好文   时间:2014-08-30 08:43:49    阅读次数:185
OCP试题解析之053-61 RMAN set command id to
61.You frequently have multiple RMAN sessions running, and you want to be able to easily identify each job via the CLIENTJNFO column of the dynamic performance view V$SESSION. What RMAN command can ...
分类:其他好文   时间:2014-08-29 20:08:08    阅读次数:261
spoj LCMSUM sigma(lcm(i,n));
Problem code: LCMSUMGiven n, calculate the sum LCM(1,n) + LCM(2,n) + .. + LCM(n,n), where LCM(i,n) denotes the Least Common Multiple of the integers i...
分类:其他好文   时间:2014-08-28 22:23:56    阅读次数:347
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