题目链接:evaluate-reverse-polish-notation
import java.util.Stack;
/**
*
Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +, -, *, /. Each opera...
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其他好文 时间:
2015-03-28 15:51:06
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130
这一周的测试课程中,我们学习了黑盒测试的一种方法:等价类划分一 等价类的基本概念 1.所谓等价类是指输入域的某个互不相交的子集合,所有等价类的并集便是整个输入域。目的在于测试用例的无冗余性。 2.划分等价类( valid / invalid )的两种情况 (1)有效等价类:检验程序是否实现...
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其他好文 时间:
2015-03-22 01:42:42
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167
题目:
Given a string containing just the characters ‘(‘, ‘)’, ‘{‘, ‘}’, ‘[’ and ‘]’, determine if the input string is valid.The brackets must close in the correct order, “()” and “()[]{}” are all valid...
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其他好文 时间:
2015-03-20 22:03:10
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125
Notes:Do not forget to clean the total and rec. 1 class Solution { 2 public: 3 int longestValidParentheses(string s) { 4 int len = s.size(...
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其他好文 时间:
2015-03-20 09:12:56
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119
Given a string containing only digits, restore it by returning all possible valid IP address combinations.For example:Given"25525511135",return["255.2...
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其他好文 时间:
2015-03-20 01:15:53
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186
problem:
Given a string containing just the characters '(', ')', '{', '}', '[' and ']',
determine if the input string is valid.
The brackets must close in the correct order, "()" and "()[]{}" are...
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其他好文 时间:
2015-03-19 22:08:16
阅读次数:
105
表单验证的步骤:1、编写函数来进行验证function valid(){ //编写验证代码 return true;}2、在提交按钮中调用函数或者在表单提交事件中调用函数onclick="return valid()"具体验证代码:1)验证文本框、下拉框非空的方式var obj=document.g...
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其他好文 时间:
2015-03-19 19:58:57
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104
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example,"A man, a plan, a canal: Pan...
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其他好文 时间:
2015-03-18 12:07:14
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111
Evaluate the value of an arithmetic expression inReverse Polish Notation.Valid operators are+,-,*,/. Each operand may be an integer or another express...
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其他好文 时间:
2015-03-18 01:09:26
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160
Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +, -, *, /. Each operand may be an integer or another expression.
Some examples:
[“2...
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其他好文 时间:
2015-03-17 21:56:20
阅读次数:
160