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Umbraco 7 特点
Umbraco 7 features at a glance The backend is mainly built on .NET C# MVC. There are some leftovers of web forms still in the core, but they are being...
分类:其他好文   时间:2015-04-13 10:55:37    阅读次数:178
Sicily 13983. Milk Scheduling
13983. Milk Scheduling Constraints Time Limit: 1 secs, Memory Limit: 256 MB Description Farmer John has N cows that need to be milked (1 Being impatient animals, some cows will r...
分类:其他好文   时间:2015-04-13 09:32:47    阅读次数:154
Python-字符串
定义: 一有序的字符序列集合,常量。用单引号引起来用双引号引起来用三重(单双均可)引号引起来# -*- coding: cp936 -*-# 字符串# python 中常见的字符串表示方式是单引号 和双引号,效果一样#内容带有单引号,就用双引号表示"It's good"#反之亦然 'You are....
分类:编程语言   时间:2015-04-13 09:22:23    阅读次数:157
ZOJ3864:Quiz for EXO-L(BFS)
Exo (Korean: ??; Chinese:爱咳嗽; often stylized as EXO) is a Chinese-South Korean boy band based in Seoul, South Korea. Formed by SM Entertainment in 2011, the group consists of twelve members separate...
分类:其他好文   时间:2015-04-13 00:29:26    阅读次数:418
HDU 1847 (博弈 找规律) Good Luck in CET-4 Everybody!
多写几个就会发现3的倍数是必败点,担心可能有例外,我一直写到第15个。。 1 #include 2 3 int main() 4 { 5 int n; 6 while(scanf("%d", &n) == 1 && n) 7 printf("%s\n", n % ...
分类:其他好文   时间:2015-04-11 22:29:49    阅读次数:101
HDU 1850 (Nim博弈 取胜方案数) Being a Good Boy in Spring Festival
考虑到Bouton定理的证明过程,设n个数的Nim和(异或和)为X,其最高位的1在第k位,那么n个数中一定有个y的第k为也是个1.将y的数量变为X xor y,那么n的数的Nim和为0,便转为先手必败局面。所以先手有多少种取法,就看n个数里面有多少个y,满足二进制的第k为是个1。 1 #includ...
分类:编程语言   时间:2015-04-11 20:37:06    阅读次数:189
使用BO API开发单词查询小软件
BO API是一款免费的数据服务API(http://www.boapi.net/),其单词查询接口http://service.boapi.net/EnWord/EnWord.ashx?key=AppKey&type=w&word=good,其中AppKey是申请的key,word是查询的单词。详...
分类:Windows程序   时间:2015-04-11 17:39:24    阅读次数:243
文章标题
1、字符串 ruby中的字符串可以使用单引号,也可以使用双引号,但对单引号的支持比较少,对双引号的支持介绍两个: (1)支持转义字符 比如: \n等 (2)字符串内的表达式内插,#{表达式} 例如:def say_goodnight(name) Result = “Good night, #{name}” end 2、数组 a = [ 1 , ‘cat’ , 3.14] b =...
分类:其他好文   时间:2015-04-10 18:01:52    阅读次数:132
Good ECU Programmer Tool to read EDC17
Which EDC17 Reader works well for a good price?BDM100, FGTECH 54, MPPS v16, kessv2.06 or any other tools/ solution is optional?Let’s hear from some ex...
分类:其他好文   时间:2015-04-10 10:51:12    阅读次数:155
hdu1850Being a Good Boy in Spring Festival NiM博弈
//当该点时p-position时,先手输 //当该点为n-position时,即a1^a2......^an = k时; //先手的第一步是使得a1^a2^.......^an^k = 0; //那么只要ai^k #include #include #include using namespace std ; const int maxn = 10000010 ; int n...
分类:编程语言   时间:2015-04-10 09:41:33    阅读次数:157
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