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Activity启动流程
转载请标明出处:一片枫叶的专栏 好吧,终于要开始讲解Activity的启动流程了,Activity的启动流程相对复杂一下,涉及到了Activity中的生命周期方法,涉及到了Android体系的CS模式,涉及到了Android中进程通讯Binder机制等等, 首先介绍一下Activity,这里引用一下 ...
分类:其他好文   时间:2017-05-22 20:02:30    阅读次数:302
分层贝叶斯学习
频率推理(Frequentist inference is a type of statistical inference that draws conclusions from sample data by emphasizing the frequency or proportion of th ...
分类:其他好文   时间:2017-05-17 18:22:22    阅读次数:240
Making User-Managed Backups-17.3、Making User-Managed Backups of Offline Tablespaces and Datafiles
17.3、Making User-Managed Backups of Offline Tablespaces and Datafiles 备份离线的表空间时。须要注意下面指导原则: (1)不能离线system表空间或活动回滚段的表空间 (2)如果一个表在表空间x中,它的索引在表空间y中。y离线,x ...
分类:其他好文   时间:2017-05-17 16:04:31    阅读次数:185
1016. Phone Bills (25)(神之模拟==)
A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, dependi ...
分类:其他好文   时间:2017-05-14 18:54:45    阅读次数:186
【转】 Difference between defining static routes with next-hop address or exit interface
For a long time I was confused about this. It was not clear to me what is the difference between setting the static route using next hop interface IP ...
分类:其他好文   时间:2017-05-14 10:32:20    阅读次数:278
解析:用 CSS3 和 JavaScript 制作径向动画菜单
原作者的解析(英文):http://creative-punch.net/2014/02/making-animated-radial-menu-css3-javascript/ 原作者的解析(译文):http://developer.51cto.com/art/201404/437152.htm ...
分类:编程语言   时间:2017-05-08 17:25:28    阅读次数:214
解决遇到动态库链接静态库
场景:二进制Link-->动态库-->第三方静态库Linux环境中需要动态库链接第三方的静态库错误:/usr/bin/ld:../../3rdpart/x64/muduo/lib/libbase.a(AsyncLogging.o):relocationR_X86_64_32against`.rodata‘cannotbeusedwhenmakingasharedobject;recompilewith-fPIC../../3rdpa..
分类:其他好文   时间:2017-05-03 01:17:18    阅读次数:229
新概念英语(1-37)Making a bookcase
What is Susan's favourite color ? A:You're working hard, Georage. What are you doing? B:I am making a bookcase. Give me that hammer please, Dan. A:Whi ...
分类:其他好文   时间:2017-04-17 11:50:37    阅读次数:162
POJ 3666 Making the Grade
传送门:http://poj.org/problem?id=3666 解题思路: dp[i][j]:代表第i个数以j结尾所花的代价。。那么dp[i][j]=fabs(a[i]-j)+min(dp[i-1][k])k<j; 实现代码: ...
分类:其他好文   时间:2017-03-28 21:42:10    阅读次数:195
poj3666 Making the Grade
思路: 离散化+dp。 实现: 总结: 1.初步学会了离散化技巧。 2.初步学会了递推优化,对完全背包的理解更深入了。 ...
分类:其他好文   时间:2017-03-18 20:35:07    阅读次数:150
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