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Mysql打开日志的方法
直接运行一下代码就可以: log-error=log-error.log log=log.log log-bin=log-bin.log log-queries-not-using-indexes=log-queries-not-using-indexes.log log-warnings=1 log-slow-queries=log-slow-query.log log-u...
分类:数据库   时间:2015-02-14 12:26:22    阅读次数:152
RabbitMQ 连接断开处理-自动恢复
Rabbitmq 官方给的NET consumer示例代码如下,但使用过程,会遇到connection断开的问题,一旦断开,这个代码就会报错,如果你的消费者端是这样的代码的话,就会导致消费者挂掉。using System;using RabbitMQ.Client;using RabbitMQ.Cl...
分类:其他好文   时间:2015-02-12 22:32:38    阅读次数:580
Java Consumer and Producer demo
import java.util.Random; import java.util.concurrent.LinkedBlockingQueue; class producer { Random rdm = new Random(); void produce( Lin...
分类:编程语言   时间:2015-02-12 20:09:01    阅读次数:216
SGU 455 Sequence analysis(Cycle detection,floyd判圈算法)
题目链接:http://acm.sgu.ru/problem.php?contest=0&problem=455Due to the slow 'mod' and 'div' operations with int64 type, all Delphi solutions for the probl...
分类:编程语言   时间:2015-02-11 21:48:03    阅读次数:322
ZOJ3430---Detect the Virus
Time Limit: 2 Seconds Memory Limit: 65536 KBOne day, Nobita found that his computer is extremely slow. After several hours’ work, he finally found that it was a virus that made his poor computer s...
分类:其他好文   时间:2015-02-10 15:21:51    阅读次数:183
angularjs填写表单
https://scotch.io/tutorials/handling-checkboxes-and-radio-buttons-in-angular-forms Angular Checkboxes and Radio But...
分类:Web程序   时间:2015-02-10 14:53:52    阅读次数:158
OGG rep运行慢的分析步骤
OGG rep运行慢的分析步骤...
分类:其他好文   时间:2015-02-09 20:21:15    阅读次数:121
JQuery学习总结
jQuery is a fast, small, and feature-rich JavaScript library. It makes things like HTML document traversal and manipulation, event handling, animation, and Ajax much simpler with an easy-to-use API that works across a multitude of browsers. With a combinat...
分类:Web程序   时间:2015-02-08 21:54:06    阅读次数:201
PostgreSQL 执行Drop Table等命令型SQL的总体流程
DROP命令(Commands)实现: /* * Drop one or more objects. * * We don't currently handle all object types here. Relations, for example, * require special handling, because (for example) indexes have add...
分类:数据库   时间:2015-02-06 14:57:50    阅读次数:290
[LeetCode]142.Linked List Cycle II
题目: Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up: Can you solve it without using extra space?分析:首先使用快慢指针技巧,如果fast指针和slow指针相遇,则说明链表存在环路。当f...
分类:其他好文   时间:2015-02-05 20:29:16    阅读次数:180
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