Original
Link:http://www.ehow.com/how_4812793_password-complexity-requirements-windows-xp.html#ixzz32PEZAbOnWhen
you create a new account in Windows X...
在正文开始之前需要介绍一个人：Sean Sexton.
来自明尼苏达双城的软件工程师，对C#和WPF有着极深的热情。最为出色的是他维护了两个博客：2,000Things You Should Know About
C#和 2,000 Things You Should Know AboutWPF.....
分类：
其他好文 时间：
2014-05-26 23:09:38
阅读次数：
282
【Grand Central Dispatch】 GCD is one of the
technologies for starting tasks asynchronously.This technology takes the thread
management code you would ....
分类：
其他好文 时间：
2014-05-26 21:59:26
阅读次数：
314
《基础篇》
http://www.cnblogs.com/lhb25/archive/2013/01/10/talks-to-help-you-become-a-better-front-end-engineer-a.html《CSS篇》
http://www.cnblogs.com/lhb25/a...
分类：
其他好文 时间：
2014-05-26 21:58:08
阅读次数：
257
介绍一个list滑动时通过一个text提示Array首字母位置的应用
/*
* Copyright (C) 2007 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file exce...
分类：
其他好文 时间：
2014-05-23 00:58:42
阅读次数：
326
介绍一个多选list
/*
* Copyright (C) 2008 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with th...
分类：
其他好文 时间：
2014-05-23 00:52:57
阅读次数：
455
介绍在在title bar上显示indeterminate progress
/*
* Copyright (C) 2007 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file ...
分类：
其他好文 时间：
2014-05-23 00:31:27
阅读次数：
352
/*
* Copyright (C) 2007 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* Yo...
分类：
其他好文 时间：
2014-05-23 00:30:50
阅读次数：
415
UVa OJ 127 - "Accordian" Patience (“手风琴”纸牌)
Time limit: 3.000 seconds
限时：3.000秒
Problem
问题
You are to simulate the playing of games of "Accordian" patience, the rules for which are as foll...
分类：
其他好文 时间：
2014-05-22 18:37:03
阅读次数：
456
【题目】
Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Your goal is to reach the last index in the minimum number of ju...
分类：
其他好文 时间：
2014-05-22 17:02:20
阅读次数：
244
