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table数据再次处理
Table的聚合函数Compute (表达式,条件)中简单的聚合函数string strSumAccount = myDs.Tables[0].Compute("SUM(AccountMoney(列))", "").ToString(); 计算datatable的列的总和分页PagedDataSou...
分类:其他好文   时间:2014-07-31 12:32:36    阅读次数:221
quartus II Warning 好的时序是设计出来的,不是约束出来的
Warning (15714): Some pins have incomplete I/O assignments. Refer to the I/O Assignment Warnings report for details解释:后续高级的芯片的 drive strength 和 slew r...
分类:其他好文   时间:2014-07-31 12:22:26    阅读次数:320
nios ii software develop handbook
1.The Nios II processor’s JTAG debug module provides a single, consistent method to connect to the processor using a JTAG download cable.2.Altera BSPs...
分类:移动开发   时间:2014-07-31 09:41:55    阅读次数:285
Subset II leetcode java
题目:Given a collection of integers that might contain duplicates, S, return all possible subsets.Note:Elements in a subset must be in non-descending o....
分类:编程语言   时间:2014-07-31 09:38:05    阅读次数:341
控制台
输出:Console.Write("hello");换行输出:Console.WriteLine("hello");获取输入的值:Console.ReadLine()控制台不关闭:Console.ReadKey();占位符:Console.WriteLine("Sum:{1} Minus:{0} R...
分类:其他好文   时间:2014-07-31 09:35:45    阅读次数:217
LeetCode "Reverse Linked List II"
Just corner case..class Solution {public: ListNode *reverseBetween(ListNode *head, int m, int n) { if(m == n) return head; ListNode *...
分类:其他好文   时间:2014-07-31 09:34:05    阅读次数:245
LeetCode "Combination Sum II"
The only difference with version I is: one number can only be used once:class Solution {public: vector > ret; struct Rec { Rec() : sum...
分类:其他好文   时间:2014-07-31 05:22:25    阅读次数:239
Path Sum II leetcode java
题目:Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.For example:Given the below binary tree and ....
分类:编程语言   时间:2014-07-31 05:22:15    阅读次数:287
Path Sum leetcode java
题目:Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given su....
分类:编程语言   时间:2014-07-31 05:21:25    阅读次数:214
FOJ 2105 Digits Count
题意:对一串数字进行抑或某数,和某数,或某数,统计某区间和的操作。思路:因为化成二进制就4位可以建4颗线段树,每颗代表一位二进制。and 如果该为是1 直接无视,是0则成段赋值为0;or 如果是0 无视,是1则成段赋值为1;xor 成段亦或,1个数和0个数交换;sum 求和;#include#inc...
分类:其他好文   时间:2014-07-31 02:22:55    阅读次数:258
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