最近刚刚接手同事的OpenResty的项目,发现对mysql,redis的操作没有用连接池,故对此进行了改造。MYSQL主要是通过mysql_pool.lua 和 dbutil.lua 来封装对数据库的操作mysql_pool.lua: 1 module("mysql_pool", package....
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数据库 时间:
2014-07-07 21:44:07
阅读次数:
591
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.For example,Given 1->2-...
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其他好文 时间:
2014-07-07 16:17:00
阅读次数:
139
nodejs + redis/mysql 连接池问题
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数据库 时间:
2014-07-07 15:05:22
阅读次数:
301
题目:Merge Two Sorted ListsMerge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the ...
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其他好文 时间:
2014-07-07 14:06:19
阅读次数:
221
Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed?
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其他好文 时间:
2014-07-07 13:07:00
阅读次数:
153
Follow up for "Remove Duplicates":What if duplicates are allowed at most twice?
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其他好文 时间:
2014-07-03 11:51:05
阅读次数:
117
Given a sorted linked list, delete all duplicates such that each element appear only once.
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其他好文 时间:
2014-07-02 00:33:49
阅读次数:
204
Redis 内部有个小型的事件驱动,它主要处理两项任务:
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其他好文 时间:
2014-06-30 12:02:01
阅读次数:
208
var indexOfSorted = function f(arr,n){
//assume : arr has been sorted
var low = 0;
var high = arr.length - 1;
var mid = (low + high) / 2;
while(high - low > 1){
if(n == arr[low]){return low...
分类:
Web程序 时间:
2014-06-30 08:54:10
阅读次数:
978
题目
There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time
complexity should be O(log (m+n)).
方法
转换为寻找第k大的数。
...
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其他好文 时间:
2014-06-30 06:05:58
阅读次数:
261