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leetcode[76] Minimum Window Substring
给定两个串,S和T,在S中找到包含T的最短子串,如果不能包含,返回空字符。Given a string S and a string T, find the minimum window in S which will contain all the characters in T in compl...
分类:Windows程序   时间:2014-11-16 01:48:32    阅读次数:349
Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Remov...
分类:其他好文   时间:2014-11-15 23:12:56    阅读次数:193
LeetCode "Find Minimum in Rotated Sorted Array II"
Similar with version I, but analysis is different. With the possibility of duplication, only ">" indicate a definite case of next search space.class S...
分类:其他好文   时间:2014-11-15 16:56:14    阅读次数:201
LeetCode "Find Minimum in Rotated Sorted Array"
There's usually a common strategy for "find *" problems - binary search: half the space can be dropped by some rules.And take care of corner cases.cla...
分类:其他好文   时间:2014-11-15 16:53:56    阅读次数:171
区别deque vector 和数组
Leetcode更新到155题了,这个easy的题acceptance却不高,我好奇的点开了它。Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(...
分类:编程语言   时间:2014-11-14 19:24:03    阅读次数:240
LeetCode——Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.pop() -- Removes the element on top of the stack.top() -- Get ...
分类:其他好文   时间:2014-11-13 20:50:45    阅读次数:197
Min Stack
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(x) -- Push element x onto stack.pop() -- Removes...
分类:其他好文   时间:2014-11-13 18:07:10    阅读次数:212
LeetCode Minimum Depth of Binary Tree
/** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { publi...
分类:其他好文   时间:2014-11-12 13:49:37    阅读次数:169
hihocoder第16周(RMQ-ST算法)
题目链接: huangjing 思路:新学会的一种算法,RMQ(Rangle Minimum Query)从名字来看,觉得就是查询最小值的,哈哈, 大白上有仔细的讲解。dp[i][j]=min(dp[i][j-1],dp[i+(1 预处理的复杂度为O(N*logN),查询就是O(1)的复杂度。 方法二:线段树解法  复杂度为O(Q*logN). 题目: 题目1 : R...
分类:编程语言   时间:2014-11-11 22:52:52    阅读次数:187
[leetcode]Triangle
问题描述: Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below. For example, given the following triangle [ [2], [3,4...
分类:其他好文   时间:2014-11-11 21:09:06    阅读次数:207
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