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查询数据表行数 然后循环查找表 添加数据到ITEMS
1 for( int i=0;i p.Field("DN").ToString()).Distinct().ToList();6 cbbDn.Items.AddRange(DnList.ToArray());7 }View Code
分类:其他好文   时间:2014-12-02 20:42:34    阅读次数:108
[leetcode]Remove Duplicates from Sorted List II
问题描述: Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5. Giv...
分类:其他好文   时间:2014-12-01 22:31:26    阅读次数:221
学生选课表
use 学生--1、 查询Student表中的所有记录的Sname、Ssex和Class列。select sname,ssex,class from student--2、 查询教师所有的单位即不重复的Depart列。select distinct depart from teacher--3、 查...
分类:其他好文   时间:2014-12-01 10:04:09    阅读次数:214
N-Queens II
Follow up for N-Queens problem.Now, instead outputting board configurations, return the total number of distinct solutions.#include#include#includeusi...
分类:其他好文   时间:2014-11-30 21:22:31    阅读次数:163
安卓官方开发文档 系统权限 System Permissions 汉英双语 1.3
Android是一个特权分隔的操作系统,每个app都会带着系统唯一标识(Linux UID和GID)来运行. 系统的某些部分也被分隔成唯一的标识. 从而Linux系统可以把每个app与其他app隔离开来.Android is a privilege-separated operating system, in which each application runs with a distinct system identity (Linux user ID and group ID). Parts of t...
分类:移动开发   时间:2014-11-30 18:48:39    阅读次数:268
Sql Server系列:聚合函数
1. SUM SUM是一个求和函数,返回指定列值的总和。SUM 只能用于数字列。其中忽略 Null 值。 语法:SUM ( [ ALL | DISTINCT ] expression ) OVER ( [ partition_by_clause ] order_by_clause ) ...
分类:数据库   时间:2014-11-30 18:38:26    阅读次数:159
LeetCode Climbing Stairs
You are climbing a stair case. It takes n steps to reach to the top.Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?思路分析:考察DP,定义ClimbWays数组,ClimbWays[n]...
分类:其他好文   时间:2014-11-29 07:06:29    阅读次数:175
Leetcode-Climbing Stairs
You are climbing a stair case. It takes n steps to reach to the top.Each time you can either climb 1 or 2 steps. In how many distinct ways can you cli...
分类:其他好文   时间:2014-11-29 07:04:53    阅读次数:187
SQLserv单表查询
作者: gw------------------------数据查询------------------------------select [all|distinct][,]...--from [,]...--where --[group by [having]]--[group by [asc|...
分类:数据库   时间:2014-11-28 21:18:35    阅读次数:255
使用max聚合函数去重
问题:jsmonth,bosscode,rewarditemid,TelNo,rewardsum这5个字段都相同即可确定这两行是重复的记录,但是计算的时候又必须用到这一行的datetime这个字段于是,首先使用select distinct jsmonth,bosscode,rewarditemid...
分类:其他好文   时间:2014-11-28 19:56:02    阅读次数:190
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