题目：
Jump Game II
Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length ...
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其他好文 时间：
2015-06-29 10:06:13
阅读次数：
103
Given a binary tree, find its maximum depth.The maximum depth is the number of nodes along the longest path from the root node down to the farthest le...
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其他好文 时间：
2015-06-27 06:24:03
阅读次数：
127
Jump Game II
Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that posi...
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其他好文 时间：
2015-06-25 21:15:22
阅读次数：
137
Givennpoints on a 2D plane, find the maximum number of points that lie on the same straight line.Hide TagsHash TableMath给出平面上的点,问一条直线最多穿过几个点.要不是之前看过这个...
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其他好文 时间：
2015-06-25 19:18:34
阅读次数：
124
最大乘积子序列思想：动态规划+最大最小数组 状态方程：考虑到负数，所以加上一个min。 max[i] = Max(max[i-1]*nums[i],min[i-1]*nums[i],nums[i]); min[i] = Min(max[i-1]*nums[i],min[i-1]*n...
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其他好文 时间：
2015-06-25 12:03:29
阅读次数：
95
Find the contiguous subarray within an array (containing at least one number) which has the largest sum.For example, given the array[?2,1,?3,4,?1,2,1,...
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其他好文 时间：
2015-06-25 10:17:54
阅读次数：
133
1. Question求二叉树的最大深度。Given a binary tree, find its maximum depth.The maximum depth is the number of nodes along the longest path from the root node do...
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其他好文 时间：
2015-06-25 00:00:30
阅读次数：
281
#104 Maximum Depth of Binary Tree
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node...
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其他好文 时间：
2015-06-24 22:38:28
阅读次数：
164
非递归： public static int maxDepth(TreeNode root){ if(root==null) return 0; Queue q=new LinkedList(); q.offer(root); int enQu...
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其他好文 时间：
2015-06-24 12:26:34
阅读次数：
98
Find the contiguous subarray within an array (containing at least one number) which has the largest product.For example, given the array [2,3,-2,4],
the contiguous subarray [2,3] has the largest produ...
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其他好文 时间：
2015-06-23 23:15:40
阅读次数：
144
