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POJ 3268 Silver Cow Party (Dijkstra)
Silver Cow Party Time Limit: 2000MS Memory Limit: 65536K Total Submissions:28457 Accepted: 12928 Description One cow from each of N farms (1 ≤ N ≤ 100 ...
分类:其他好文   时间:2018-07-30 21:28:42    阅读次数:144
luogu P1821 Silver Cow Party
题目描述 One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow party to be held at farm #X (1 ≤ X ≤ N). A ...
分类:其他好文   时间:2018-07-14 16:46:21    阅读次数:185
POJ 3268 Silver Cow Party
题意:给定顶点个数,边的个数,目的地,求顶点到边的往返最大距离 解题思路:目的地到顶点的是标准的Dijkstra,顶点到目的地的只需要把矩阵转置一下就OKay了 ...
分类:其他好文   时间:2018-06-25 23:01:05    阅读次数:325
poj3268 Silver Cow Party(两次dijkstra)
https://vjudge.net/problem/POJ-3268 一开始floyd超时了。。 对正图定点求最短,对逆图定点求最短,得到任意点到定点的往返最短路。 ...
分类:其他好文   时间:2018-05-09 19:30:31    阅读次数:140
Luogu P1821 [USACO07FEB]银牛派对Silver Cow Party
P1821 [USACO07FEB]银牛派对Silver Cow Party 题目描述 One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow part ...
分类:其他好文   时间:2018-04-19 19:34:53    阅读次数:190
POJ-3268 Silver Cow Party---正向+反向Dijkstra
题目链接: https://vjudge.net/problem/POJ-3268 题目大意: 有编号为1-N的牛,它们之间存在一些单向的路径。给定一头牛的编号X,其他牛要去拜访它并且拜访完之后要返回自己原来的位置,求所有牛从开始到回家的时间是多少? 思路: 所有牛都回到了家所花费的时间就是这些牛中 ...
分类:其他好文   时间:2018-04-07 12:47:44    阅读次数:145
Silver Cow Party
One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow party to be held at farm #X (1 ≤X ≤ N). A total ...
分类:其他好文   时间:2018-03-22 01:45:34    阅读次数:178
洛谷 P1821 [USACO07FEB]银牛派对Silver Cow Party
P1821 [USACO07FEB]银牛派对Silver Cow Party P1821 [USACO07FEB]银牛派对Silver Cow Party P1821 [USACO07FEB]银牛派对Silver Cow Party 题目描述 One cow from each of N farms ...
分类:其他好文   时间:2018-02-04 15:37:36    阅读次数:166
洛谷——P1821 [USACO07FEB]银牛派对Silver Cow Party
P1821 [USACO07FEB]银牛派对Silver Cow Party 题目描述 One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to attend the big cow part ...
分类:其他好文   时间:2018-01-06 16:01:03    阅读次数:166
P1821 [USACO07FEB]银牛派对Silver Cow Party
P1821 [USACO07FEB]银牛派对Silver Cow Party我当时看着邻接矩阵存的下,就想来一发floyed,然后发现了很多问题。floyed的判定条件非常严格,否则会挂。初始化为inf if(d[i][k]+d[k][j]<d[i][j]&&d[i][k]!=inf&&d[k][j ...
分类:其他好文   时间:2017-10-10 20:45:46    阅读次数:234
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