Speed has always been one of Chrome's primary missions, ever since it was included as one of the founding principles in 2008. But speed is about more ...
分类：
编程语言 时间：
2015-03-19 18:15:02
阅读次数：
289
题目：Quoit DesignTime Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 136 Accepted Submission(s): 77 Problem DescriptionHave you ever played quoit in a p...
分类：
其他好文 时间：
2015-03-19 11:32:56
阅读次数：
150
微软近期Open的职位:Job Title: Senior Software EngineerLocation: Shanghai, ChinaHave you ever imagined the world with infinite amount of storage available and...
分类：
其他好文 时间：
2015-03-17 23:35:21
阅读次数：
157
如题。。http://www.spoj.com/problems/WILLITST/#includelong long n;int main(){ scanf("%lld",&n); while(n>1){ if (n==3||n==6){printf("NIE\n");r...
分类：
其他好文 时间：
2015-03-06 22:01:34
阅读次数：
266
Problem Description
Have you ever heard the story of Blue.Mary, the great civil engineer? Unlike Mr. Wolowitz, Dr. Blue.Mary has accomplished many great projects, one of which is the Guanghua Building.
The public opinion is that Guanghua Building is no...
分类：
编程语言 时间：
2015-03-05 22:24:55
阅读次数：
265
Problem Description
Nowadays, we all know that Computer College is the biggest department in HDU. But, maybe you don't know that Computer College had ever been split into Computer College and Software College in 2002.
The splitting is absolutely a big even...
分类：
其他好文 时间：
2015-03-04 19:14:57
阅读次数：
176
http://www.hjenglish.com/new/p718262/My little friend Seth, who is eight, pronounces this the best film he has ever seen.我八岁的小伙伴，赛斯，声称这是他看过的最棒的电影。And ...
分类：
其他好文 时间：
2015-02-25 19:51:10
阅读次数：
164
Largest collection of FREE Microsoft eBooks ever, including: Windows 8.1, Windows 8, Windows 7, Office 2013, Office 365, Office 2010, SharePoint 2013,...
分类：
其他好文 时间：
2015-02-25 10:18:09
阅读次数：
245
Lotto
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 1610 Accepted Submission(s): 792
Problem Description
In a Lotto I have ever pl...
分类：
其他好文 时间：
2015-02-19 16:19:56
阅读次数：
212
在数据库中创建表如下，统计每个Task对应的TaskNote有多少条？第一种解决方案：select t.TaskId, (select count(n.ID) from TaskNote n where n.TaskId = t.TaskId) 'Notes', --exec ever...
分类：
数据库 时间：
2015-02-12 22:39:41
阅读次数：
263
