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搜索关键字:二分搜索    ( 480个结果
*Sqrt(x)
Q:Implementint sqrt(int x).Compute and return the square root ofx.A:这里给出两种实现方法:一是二分搜索,二是牛顿迭代法。1. 二分搜索对于一个非负数n,它的平方根不会大于(n/2+1)。在[0, n/2+1]这个范围内可以进行二分搜...
分类:其他好文   时间:2015-09-16 06:24:24    阅读次数:192
hdu 5432 Pyramid Split(二分搜索)
Problem DescriptionXiao Ming is a citizen who's good at playing,he has lot's of gold cones which have square undersides,let's call them pyramids.Anyon...
分类:其他好文   时间:2015-09-12 22:22:49    阅读次数:370
查找(二):彻底理解红黑树和平衡查找树
平衡查找树在之前的二分搜索和二叉查找树中已经能够很好地解决查找的问题了,但是它们在最坏情况下的性能还是很糟糕,我们可以在查找二叉树中,每次动态插入或删除某结点时,都重新构造为完全二叉树,但是这样代价太大,所以就引出了平衡查找树。详细的数学定义就不给出了,因为既不直观也记不住,直接给出一个平衡二叉树的...
分类:其他好文   时间:2015-09-10 12:27:57    阅读次数:253
Search a 2D Matrix (Easy,二分搜索)
题目描述:Write an efficient algorithm that searches for a value in an mxnmatrix.This matrix has the following properties:Integers in each row are sorted f...
分类:其他好文   时间:2015-09-09 16:24:11    阅读次数:194
Binary Search(Easy,二分搜索)
题目描述:For a given sorted array (ascending order) and atargetnumber, find the first index of this number inO(log n)time complexity.If the target number ...
分类:其他好文   时间:2015-09-09 16:21:30    阅读次数:195
Search Insert Position(Easy,二分搜索)
题目描述:Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted ...
分类:其他好文   时间:2015-09-09 16:21:05    阅读次数:170
poj 1759 Garland (二分搜索之其他)
DescriptionThe New Year garland consists of N lamps attached to a common wire that hangs down on the ends to which outermost lamps are affixed. The wi...
分类:其他好文   时间:2015-09-05 16:26:00    阅读次数:239
poj 3662 Telephone Lines(好题!!!二分搜索+dijkstra)
DescriptionFarmer John wants to set up a telephone line at his farm. Unfortunately, the phone company is uncooperative, so he needs to pay for some of...
分类:其他好文   时间:2015-09-05 16:25:44    阅读次数:212
poj 3685 Matrix(二分搜索之查找第k大的值)
DescriptionGiven a N × N matrix A, whose element in the i-th row and j-th column Aij is an number that equals i2 + 100000 × i + j2 - 100000 × j + i × ...
分类:其他好文   时间:2015-09-04 21:09:47    阅读次数:188
poj 3579 Median (二分搜索之查找第k大的值)
DescriptionGiven N numbers, X1, X2, ... , XN, let us calculate the difference of every pair of numbers: ∣Xi - Xj∣ (1 ≤ i < j ≤ N). We can get C(N,2) d...
分类:其他好文   时间:2015-09-04 19:53:04    阅读次数:902
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