calabash-android是一个单元测试的工具,用来测试UI。这个特点非常适合来刷应用程序的广告。本文以一个简单的例子来教大家使用calabash-anroid来刷应用程序的广告。代码下载地址:https://github.com/bigconvience/poker_hu
在使用本文提供的例子进行测试前,请先确保安装好测试环境,可参考此文:Windows 安装Calabash-A...
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移动开发 时间:
2014-09-09 13:00:58
阅读次数:
298
We Need Medicine
Time Limit: 10 Seconds Memory Limit: 65536 KB Special Judge
A terrible disease broke out! The disease was caused by a new type of virus, which will lead to lethal lymp...
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其他好文 时间:
2014-09-09 12:55:12
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301
A Volcanic Island
Time Limit: 2 Seconds Memory Limit: 65536 KB Special Judge
An underwater volcano has erupted massively in somewhere of the deep Atlantis Ocean. This large eruption le...
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其他好文 时间:
2014-09-09 12:53:58
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137
Pretty Poem
Time Limit: 2 Seconds Memory Limit: 65536 KB
Poetry is a form of literature that uses aesthetic and rhythmic qualities of language. There are many famous poets in the contempo...
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其他好文 时间:
2014-09-09 12:48:38
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254
he Himalayas
Time Limit: 2 Seconds Memory Limit: 65536 KB
As an artist, Bob usually need to travel around the world. He made a lot of sketch of scenery on his journey. A famous spot he ha...
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其他好文 时间:
2014-09-09 12:48:18
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214
Generalized Palindromic NumberTime Limit: 2 Seconds Memory Limit: 65536 KBA number that will be the same when it is written forwards or backwards i...
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其他好文 时间:
2014-09-09 11:19:48
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351
昨天网赛的C题,我负责的,题意有些模模糊糊的我首先弄清楚了题意,即要求一个patrol是否可能巡视过所有的点,首先整个图要是连通的,这个在建图的时候边用下并查集即可,然后某些点装了传感器,传感器应该要全部都响应过才行,即L==k否则直接输出No,然后就是重点,给出的传感器的响应先后顺序,我们要在图上...
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其他好文 时间:
2014-09-09 11:00:58
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163
ZOJ Problem Set - 3818
Pretty Poem
Time Limit: 2 Seconds
Memory Limit: 65536 KB
Poetry is a form of literature that uses aesthetic and rhythmic qualities of language. There are many f...
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其他好文 时间:
2014-09-08 10:54:26
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272
Pretty Poem
Time Limit: 2 Seconds Memory Limit: 65536 KB
Poetry is a form of literature that uses aesthetic and rhythmic qualities of language. There are many famous poets in the contempora...
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其他好文 时间:
2014-09-08 10:52:56
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334
题意:
一幅图某些点有监视器 监视器只记录第一次路过的时间 问 给出路线序列 是否存在满足序列的情况下遍历整幅图的点
思路:
不要想割点 割点无法处理在一个双连通分量内的多个监视器 这题就是贪心+搜索
贪心就是尽量多的使用不违背序列的点 那么我们先把序列里的第一个点和不存在监视器的点加入图 并将他们连边 对于其他的序列中的点 如果这个点存在与第一个点所形成的连通块连接的...
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其他好文 时间:
2014-09-08 10:52:26
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216