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153. Find Minimum in Rotated Sorted Array
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). F ...
分类:其他好文   时间:2019-09-13 11:12:10    阅读次数:97
154. Find Minimum in Rotated Sorted Array II
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). F ...
分类:其他好文   时间:2019-09-13 10:39:49    阅读次数:100
最小费用流
// algorithm_minimum_cost_stream.cpp : 此文件包含 "main" 函数。程序执行将在此处开始并结束。////https://blog.csdn.net/qq_43824791/article/details/93238445#include "pch.h"#in ...
分类:其他好文   时间:2019-09-13 01:07:03    阅读次数:90
[虚拟机OA]Team Formation 2 团队构成
FC Codelona is trying to assemble a team from a roster of available players. They have a minimum number of players they want to sign and each player n ...
分类:其他好文   时间:2019-09-12 10:24:12    阅读次数:353
TP50、TP90、TP99、TP999
TP=Top Percentile,Top百分数,是一个统计学里的术语,与平均数、中位数都是一类。TP50、TP90和TP99等指标常用于系统性能监控场景,指高于50%、90%、99%等百分线的情况。首先给出Google到的答案:The tp90 is a minimum time under wh ...
分类:其他好文   时间:2019-09-11 18:01:56    阅读次数:126
NI CWGraph 显示波形图
ptrWaveBox.Axes(1).Maximum = 1000 ptrWaveBox.Axes(2).Maximum = 20 ptrWaveBox.Axes(2).Minimum = 0 Dim fTemp(2000) As Single For n = 0 To iPixel - 1 fTe... ...
分类:其他好文   时间:2019-09-09 19:09:10    阅读次数:73
LeetCode 857. Minimum Cost to Hire K Workers
合法的pay group里所有worker的比例是一样的,即 wage1/wage2 = quality1/quality2 推出 wage1/quality1 = wage2/quality2。 这就好办了,定义 ratio_i = wage_i/quality_i。对于一个group,ratio ...
分类:其他好文   时间:2019-09-08 12:26:35    阅读次数:73
hdu-4738.Caocao's Bridges(图中权值最小的桥)
Caocao's Bridges Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10933 Accepted Submission(s): 30 ...
分类:其他好文   时间:2019-09-08 00:21:23    阅读次数:69
Palindrome Partitioning II 解答
Question Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome par ...
分类:其他好文   时间:2019-09-07 00:49:44    阅读次数:101
数据分析(六)
加权平均值 样本:S = [s1, s2, ..., sn] 权重:W = [w1, w2, ..., wn] 加权平均值:a = (s1w1+s2w2+...+snwn)/(w1+w2+...+wn) np.average(closing_prices, weights=volumes) ...
分类:其他好文   时间:2019-09-04 13:32:47    阅读次数:85
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