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Aizu 2304 Reverse Roads
原题链接:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=2304题意:给你一个网络,其中每条边的容量是1,你可以通过调整边的方向来获得更大的流量,现在问你能获得的最大流量是多少。并且输出更改方向的边的编号。题解:就每条边弄成无向的,...
分类:其他好文   时间:2015-10-01 23:04:10    阅读次数:337
[LeetCode In C++] 2. Add Two Numbers
题目:You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a sing...
分类:编程语言   时间:2015-10-01 23:03:14    阅读次数:346
Aizu 2304 Reverse Roads
把有向图修改成无向图,并保证每条边的流量守恒并满足有向容量(即abs(flow(u,v) - flow(v,u)) using namespace std;const int N = 301,M = N*(N-1);int n,m;int hd[N],nx[M],to[M],cap[M],ect;i...
分类:其他好文   时间:2015-10-01 19:09:13    阅读次数:204
Add Two Numbers
题目: You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a s.....
分类:其他好文   时间:2015-10-01 14:02:44    阅读次数:141
将中缀式转化为逆波兰式 (栈)
逆波兰式:Reverse Polish notation,RPN,,也叫后缀表达式,将运算符写在操作数之后数据结构:两个栈S1和S2。S1临时存储运算符,S2存储最终结果。算法:(1)若取出的字符是操作数,则分析出完整的运算数,该操作数直接送入S2栈(2)若取出的字符是运算符,则将该运算符与S1栈栈...
分类:其他好文   时间:2015-10-01 11:40:42    阅读次数:280
LeetCode #2 Add Two Numbers (M)
[Problem]You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain ...
分类:其他好文   时间:2015-09-30 23:16:00    阅读次数:186
Evaluate Reverse Polish Notation(堆栈)
Evaluate the value of an arithmetic expression inReverse Polish Notation.Valid operators are+,-,*,/. Each operand may be an integer or another express...
分类:其他好文   时间:2015-09-28 22:12:11    阅读次数:251
git rev-list
git-rev-list - Lists commit objects in reverse chronological order按照时间顺序倒序排列的commitUpdate:If all you need is a commit count, and you're running a newe...
分类:其他好文   时间:2015-09-27 12:35:25    阅读次数:324
Reverse Linked List
Reverse a singly linked list. /** * Definition for singly-linked list. * struct ListNode { * int val; * struct ListNode *next; * }; */ struct ListNode...
分类:其他好文   时间:2015-09-25 09:31:26    阅读次数:124
Reverse的方法
方法一: reverse ArrayList1 private void reverse(ArrayList nums, int start, int end) {2 for (int i = start, j = end; i < j; i++, j--) {3 ...
分类:其他好文   时间:2015-09-25 07:21:46    阅读次数:174
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