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[leetcode] Reverse Linked List II
Reverse a linked list from position m to n. Do it in-place and in one-pass.
分类:其他好文   时间:2014-07-02 20:12:57    阅读次数:182
[leetcode] Partition List
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x.
分类:其他好文   时间:2014-07-02 10:01:21    阅读次数:173
LeetCode: Sort List [148]
【题目】 Sort a linked list in O(n log n) time using constant space complexity. 【题意】 排序一个链表,要求时间复杂度O(nlogn),使用常量空间 【思路】 nlogn的复杂度,用归并排序求解...
分类:其他好文   时间:2014-07-02 09:25:40    阅读次数:252
Leetcode:Sort List 对单链表归并排序
Sort a linked list in O(n log n) time using constant space complexity. 看到O(n log n)的排序算法,适合单链表的首先想到的就是归并排序 /** * Definition for singly-linked list. * struct ListNode { * int val; * Lis...
分类:其他好文   时间:2014-07-02 08:47:34    阅读次数:239
LeetCode: Insertion Sort List [147]
【题目】 Sort a linked list using insertion sort. 【题意】 用插入排序方法排序链表 【思路】 直接搞...
分类:其他好文   时间:2014-07-02 08:33:49    阅读次数:200
Leetcode:Merge Two Sorted Lists 合并两个有序单链表
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 代码如下: * Definition for singly-linked list. * struct L...
分类:其他好文   时间:2014-07-02 07:23:59    阅读次数:159
Linked List Cycle
题目 Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? 方法 /** * Definition for singly-linked list. * class ListNode { ...
分类:其他好文   时间:2014-07-01 11:31:40    阅读次数:178
Linked List Cycle II
题目 Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up: Can you solve it without using extra space? 方法 public ListNode de...
分类:其他好文   时间:2014-07-01 11:30:58    阅读次数:200
Flatten Binary Tree to Linked List
题目 Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / 2 5 / \ 3 4 6 The flattened tree should look lik...
分类:其他好文   时间:2014-07-01 08:03:10    阅读次数:127
Copy List with Random Pointer
题目 A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 方法 publi...
分类:其他好文   时间:2014-07-01 07:49:33    阅读次数:186
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