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01-复杂度2. Maximum Subsequence Sum (25)
Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj } where 1 =0)25 {26 ...
分类:其他好文   时间:2015-04-07 22:58:11    阅读次数:214
构建基于Jenkins + Github的持续集成环境
搭建持续集成首先要了解什么是持续集成,带着明确的目标去搭建持续集成环境才能让我们少走很多弯路。持续集成(Continuous integration)简称CI,是一种软件开发的实践,可以让团队在持续集成的基础上收到反馈并加以改进,不必等到开发的后期才寻找和修复缺陷。当然要明白的是持续集成环境的搭建也...
分类:其他好文   时间:2015-03-30 18:31:46    阅读次数:234
01-复杂度2. Maximum Subsequence Sum (25)
Given a sequence of K integers { N1, N2, ..., NK}. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj} where 1 //using namespace std;//cons...
分类:其他好文   时间:2015-03-19 16:16:34    阅读次数:163
ggplot2 学习笔记 (持续更新.....)
1. 目前有四种主题theme_gray(), theme_bw() , theme_minimal(),theme_classic()2. X轴设置刻度scale_x_continuous(limits=c(1950,2000),breaks=seq(1950,2000,5))3. Bar & L...
分类:其他好文   时间:2015-03-19 14:46:23    阅读次数:172
A1007. Maximum Subsequence Sum (25)
Given a sequence of K integers { N1, N2, ..., NK}. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj} where 1 5 #include 6 #include 7 #...
分类:其他好文   时间:2015-03-16 19:10:05    阅读次数:109
openStack CI(Continuous interaction)/CD(Continuous delivery) Gerrit/Jenkins安装及集成,插件配置
preFace:CI/CD practice part contains the following action items and fields of expertise:Gerrit installation and basic configuration? Jenkins installat...
分类:其他好文   时间:2015-03-12 14:51:56    阅读次数:1013
OpenCV.2.Computer.Vision.Application.Programming.Cookbook--Efficient scanning of continuous images
#include void colorReduce(cv::Mat &image, int div=64) { int nr= image.rows; // number of rows int nc= image.cols * image.channels(); // total number of elements per line if (image.isContinuo...
分类:移动开发   时间:2015-03-10 21:36:15    阅读次数:169
数据结构练习 01-复杂度2. Maximum Subsequence Sum (25)
Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj } where 1 using namespace std;int Ma...
分类:其他好文   时间:2015-03-05 00:10:17    阅读次数:202
用R语言 画条形图(基于ggplot2包)
1.用qplot(x,data=data,geom.=”bar”,weight=y)+scale_y_continuous("y")画出y关于x的条形。图中提示binwidth这里是指矩形的宽度,指定之后如下qplot(x,data=data,geom="bar",weight=y,binwidth...
分类:编程语言   时间:2015-03-02 16:47:38    阅读次数:1895
swift UI专项训练32 Stepper微调控件
跟滑块对应的时Stepper微调控件,有时候我们需要精确地变动,那么就不能用滑块来做,Stepper每次以一个固定的值来增加或者减少,它的设置跟滑块比就比较相似了: 也有最大值最小值和当前值,不同的是有Step这个值,也就是我们加减时的固定值,叫做步进值。它的行为有三种: Autorepeat是按住自动重复 Continuous是连续触发值变更事件 Wrap是达到极值后反转...
分类:编程语言   时间:2015-03-02 13:08:43    阅读次数:145
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