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JavaScript里的循环方法:forEach,for-in,for-of
JavaScript诞生已经有20多年了,我们一直使用的用来循环一个数组的方法是这样的: 自从JavaScript5起,我们开始可以使用内置的forEach方法: 写法简单了许多,但也有短处:你不能中断循环(使用break语句或使用return语句。 JavaScript里还有一种循环方法:for– ...
分类:编程语言   时间:2016-09-24 13:41:27    阅读次数:135
21. Merge Two Sorted Lists
恢复内容开始 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思 ...
分类:其他好文   时间:2016-09-24 11:59:23    阅读次数:114
INV(库存管理)
物料 1 PROCEDURE update_item(p_init_msg_list IN VARCHAR2 DEFAULT fnd_api.g_false, 2 x_return_status OUT NOCOPY VARCHAR2, 3 x_msg_count OUT NOCOPY NUMBER ...
分类:其他好文   时间:2016-09-24 11:56:44    阅读次数:292
Reverse Words in a string
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C pr ...
分类:其他好文   时间:2016-09-24 07:06:07    阅读次数:179
364. Nested List Weight Sum II
Given a nested list of integers, return the sum of all integers in the list weighted by their depth. Each element is either an integer, or a list -- w ...
分类:其他好文   时间:2016-09-24 07:04:21    阅读次数:190
301. Remove Invalid Parentheses
Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may cont ...
分类:其他好文   时间:2016-09-24 07:03:55    阅读次数:122
重做257. Binary Tree Paths
Given a binary tree, return all root-to-leaf paths. For example, given the following binary tree: All root-to-leaf paths are: Solution1: 用string是最方便的。 ...
分类:其他好文   时间:2016-09-24 07:03:29    阅读次数:201
339. Nested List Weight Sum
Given a nested list of integers, return the sum of all integers in the list weighted by their depth. Each element is either an integer, or a list -- w ...
分类:其他好文   时间:2016-09-24 07:03:26    阅读次数:113
获取电脑系统当前时间
public static String parseDate(){ Date d = new Date(); SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); return sdf.format(d); } ...
分类:其他好文   时间:2016-09-24 00:45:14    阅读次数:167
jquery的isNumeric方法
//判断是否为数字isNumeric: function( obj ) { //isFinite判断是否为有限的数字 return !isNaN( parseFloat(obj) ) && isFinite( obj );} ...
分类:Web程序   时间:2016-09-24 00:43:55    阅读次数:201
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