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HNUSTOJ-1543 字符串的运算再现
1543: 字符串的运算再现 题目描述 我们对字符串 S 做了以下定义:1. S ^ k表示由k个字符串S构成的新字符串。 例如, S = "abc", k = 3, 则S ^ k = "abcabcabc"2. Subsequence(S) 表示由字符串S的所有非空子序列构成的字符串集合。例如, ...
分类:其他好文   时间:2017-08-24 17:52:52    阅读次数:129
[LintCode] Distinct Subsequence
Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which is formed from t ...
分类:其他好文   时间:2017-08-24 10:43:40    阅读次数:244
[Coding Made Simple] Longest Increasing Subsequence
Given an array, find the longest increasing subsequence in this array. The same problem link. [LintCode] Longest Increasing Subsequence ...
分类:其他好文   时间:2017-08-24 10:31:38    阅读次数:95
[Coding Made Simple] Maximum Sum Subsequence Non-adjacent
Given an array of positive number, find maximum sum subsequence such that elements in this subsequence are not adjacent to each other. Recursive formu ...
分类:其他好文   时间:2017-08-22 13:55:00    阅读次数:179
[Coding Made Simple] Longest Bitonic Subsequence
Find longest bitonic subsequence in given array. Bitonic subsequence first increases then decreases. Same problem link Longest Bitonic Subsequence ...
分类:其他好文   时间:2017-08-22 13:16:35    阅读次数:138
HDU 6155 Subsequence Count 线段树维护矩阵
Subsequence Count Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 256000/256000 K (Java/Others) Problem Description Given a binary string S[1,.. ...
分类:其他好文   时间:2017-08-21 17:26:37    阅读次数:363
2017中国大学生程序设计竞赛 - 网络选拔赛 HDU 6155 Subsequence Count 矩阵快速幂
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6155 题意: 题解来自:http://www.cnblogs.com/iRedBean/p/7398272.html 先考虑dp求01串的不同子序列的个数。 dp[i][j]表示用前i个字符组成的以j为 ...
分类:其他好文   时间:2017-08-20 22:44:52    阅读次数:437
POJ 1458 - Common Subsequence(最长公共子序列) 题解
此文为博主原创题解,转载时请通知博主,并把原文链接放在正文醒目位置。 题目链接:http://poj.org/problem?id=1458 题目大意: 有若干组数据,每组给出两个字符串(中间用任意数量的空格间隔),输出这两个字符串最长公共子序列的长度。每次输出后换行。 分析: 动态规划求LCS,f ...
分类:其他好文   时间:2017-08-20 10:07:20    阅读次数:200
hdu 6155 - Subsequence Count
话说这题比赛时候过的好少,连题都没读TOT 先考虑dp求01串的不同子序列的个数。 dp[i][j]表示用前i个字符组成的以j为结尾的01串个数。 如果第i个字符为0,则dp[i][0] = dp[i-1][1] + dp[i-1][0] + 1,dp[i][1] = dp[i-1][1] 如果第i ...
分类:其他好文   时间:2017-08-20 00:49:11    阅读次数:289
Longest Ordered Subsequence与最少拦截系统 DP+贪心(最长上升子序列及最少序列个数)
Longest Ordered Subsequence A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence ( a1, a2, ... ...
分类:其他好文   时间:2017-08-15 22:52:24    阅读次数:130
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