Check nagios配置文件报错例如以下：[nagios@2 etc]$
/usr/local/nagios/bin/nagios -v /usr/local/nagios/etc/nagios.cfgNagios Core
4.0.6Copyright (c) 2009-present Nag...
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移动开发 时间：
2014-05-27 00:07:04
阅读次数：
364
Original
Link:http://www.ehow.com/how_4812793_password-complexity-requirements-windows-xp.html#ixzz32PEZAbOnWhen
you create a new account in Windows X...
在正文开始之前需要介绍一个人：Sean Sexton.
来自明尼苏达双城的软件工程师，对C#和WPF有着极深的热情。最为出色的是他维护了两个博客：2,000Things You Should Know About
C#和 2,000 Things You Should Know AboutWPF.....
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其他好文 时间：
2014-05-26 23:09:38
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282
介绍一个list滑动时通过一个text提示Array首字母位置的应用
/*
* Copyright (C) 2007 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file exce...
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其他好文 时间：
2014-05-23 00:58:42
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326
介绍一个多选list
/*
* Copyright (C) 2008 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with th...
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其他好文 时间：
2014-05-23 00:52:57
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455
H. Happy Reversal
64-bit integer IO format: %lld
Java class name: Main
Elfness is studying in an operation "NOT".
For a binary number A, if we do operation "NOT A", after that, all digit...
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移动开发 时间：
2014-05-23 00:43:49
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430
介绍在在title bar上显示indeterminate progress
/*
* Copyright (C) 2007 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file ...
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其他好文 时间：
2014-05-23 00:31:27
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352
/*
* Copyright (C) 2007 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* Yo...
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其他好文 时间：
2014-05-23 00:30:50
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415
UVa OJ 127 - "Accordian" Patience (“手风琴”纸牌)
Time limit: 3.000 seconds
限时：3.000秒
Problem
问题
You are to simulate the playing of games of "Accordian" patience, the rules for which are as foll...
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其他好文 时间：
2014-05-22 18:37:03
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456
【题目】
Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Your goal is to reach the last index in the minimum number of ju...
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其他好文 时间：
2014-05-22 17:02:20
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244
