这里因为是有序的,可以利用这个有序性来进行查找left=0,right=num.length-1;while(lefttarget) right--; else return true;}return false;
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其他好文 时间:
2015-08-12 21:30:14
阅读次数:
83
思路:只需遍历一次数组,利用HashMap保存数组元素和下标,如果数组元素存在HashMap的key中,则返回结果,如果不存在,则put到HashMap中,注意,这种遍历保证了数组的下标肯定不小于HashMap中的下标。Java代码: public int[] twoSum(int[] num...
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其他好文 时间:
2015-08-08 14:51:39
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115
Two Sum
Given an array of integers, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to th...
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其他好文 时间:
2015-08-04 23:00:26
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104
Given an array of integers, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two numbers such that they add up to the target, where in...
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其他好文 时间:
2015-08-02 18:20:21
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112
1Given an arrayof integers, find two numbers such that they add up to a specific targetnumber.The functiontwoSum should return indices of the two numbers such that they add up to thetarget, where inde...
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其他好文 时间:
2015-07-21 12:56:09
阅读次数:
93
在解决本道题时,最先想到的思路是用两个指针,一个在前,一个紧随其后。然后后面的指针的不断向后移动直到找到匹配的元素或者到达数组的末端。再不断进行下次迭代。代码如下:#include
#include
using namespace std;class Solution {
public:
vector twoSum(vector& nu...
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其他好文 时间:
2015-07-10 09:32:42
阅读次数:
128
Given an array of integers, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two nu...
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其他好文 时间:
2015-07-10 00:14:30
阅读次数:
116
1 Two Sum链接:https://leetcode.com/problems/two-sum/
问题描述:
Given an array of integers, find two numbers such that they add up to a specific target number.The function twoSum should return indices of t...
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其他好文 时间:
2015-07-08 14:39:14
阅读次数:
131
题目描述:给定一个整数数组,找到其中的两个数之和等于目标值,返回两个数的索引值index1和index2,保证index1 twoSum(vector &numbers, int target) { 2 vector result; 3 for(int i=0;i类型...
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其他好文 时间:
2015-07-06 23:20:31
阅读次数:
121
https://leetcode.com/problems/two-sum/Given an array of integers, find two numbers such that they add up to a specific target number.The function twoS...
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其他好文 时间:
2015-06-28 17:31:17
阅读次数:
127