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(*medium)LeetCode 233.Number of Digit One
Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n.For example:Given n = 13,Return 6...
分类:其他好文   时间:2015-08-04 20:58:01    阅读次数:110
[LeetCode-JAVA] Permutations II
题目:Given a collection of numbers that might contain duplicates, return all possible unique permutations.For example,[1,1,2]have the following unique p...
分类:编程语言   时间:2015-08-04 20:54:14    阅读次数:187
java中执行js代码
要在java中执行js代码,首先明白,java不支持浏览器本身的方法。支持自定义的js方法,否则会报错先新建一个js文件:jsss.js内容如下: function aa(a,b){ return a+b;}然后在java中写代码:public class ZipTest { ...
分类:编程语言   时间:2015-08-04 20:50:53    阅读次数:105
Valid Anagram
题目描述:Given two strings s and t, write a function to determine if t is an anagram of s.For example,s = "anagram", t = "nagaram", return true.s = "rat",...
分类:其他好文   时间:2015-08-04 20:48:34    阅读次数:97
(medium)LeetCode 238.Product of Array Except Self
Given an array ofnintegers wheren> 1,nums, return an arrayoutputsuch thatoutput[i]is equal to the product of all the elements ofnumsexceptnums[i].Solv...
分类:其他好文   时间:2015-08-04 20:44:27    阅读次数:193
[Jobdu]题目1367:二叉搜索树的后序遍历序列
1 #include 2 3 int isValid(int a[], int low, int high) { 4 if (low >= high) 5 return 1; 6 7 int root = a[high]; 8 int i = lo...
分类:其他好文   时间:2015-08-04 20:41:51    阅读次数:144
LeetCode#46 Permutations
Problem Definition:Given a collection of numbers, return all possible permutations. For example,[1,2,3] have the following permutations:[1,2,3], [1,3,...
分类:其他好文   时间:2015-08-04 20:39:40    阅读次数:148
Js获取后台集合List里面值和下标的方法
首先用的是struts2的框架,分两种情况: 1. 集合list里面是值,不是对象 public class myTest { ArrayList mylist; public ArrayList getMylist() { return mylist; } public void setMylist(ArrayList mylist) { this.mylist =...
分类:Web程序   时间:2015-08-04 19:15:09    阅读次数:153
使用config自定义配置
publicclassOrdersSection:ConfigurationSection { [ConfigurationProperty("companyID",IsRequired=true)] publicstringCompanyID { get { return(st...
分类:其他好文   时间:2015-08-04 19:05:28    阅读次数:95
javascript 常用函数
//获取元素的样式值。 function getStyle(elem,name){ if(elem.style[name]){ return elem.style[name]; }else if(elem.currentStyle){ return elem.currentStyle[name]; ...
分类:编程语言   时间:2015-08-04 18:56:55    阅读次数:127
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