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Evaluate Reverse Polish Notation
说明:使用一个数字栈即可。(也可用数组链表模拟栈)
分类:其他好文   时间:2014-08-10 01:41:49    阅读次数:191
STL vector中的rbegin方法(5)
public member function std::vector::rbegin C++98 C++11 reverse_iterator rbegin() noexcept; const_reverse_iterator rbegin() const noexcept; Return reverse iterator...
分类:其他好文   时间:2014-08-09 23:22:42    阅读次数:684
LeetCode第七题,Reverse Integer
题目 Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask...
分类:其他好文   时间:2014-08-09 00:13:36    阅读次数:309
Evaluate Reverse Polish Notation
Evaluate the value of an arithmetic expression in Reverse Polish Notation.Valid operators are +, -, *, /. Each operand may be an integer or another ex...
分类:其他好文   时间:2014-08-08 23:49:56    阅读次数:314
(LeetCode)Reverse Words in a String
思路:依次遍历输入string的每一个字符, 若当前字符是空格,则循环继续;否则,读取一个单词,并将其加入新string的头部;重复上述步骤。 1 void reverseWords( string &s ) { 2 string rStr = ""; 3 int size = s....
分类:其他好文   时间:2014-08-08 21:13:56    阅读次数:207
【LeetCode】Reverse Linked List II
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Given m, n satisfy t...
分类:其他好文   时间:2014-08-07 19:02:50    阅读次数:251
Add Two Numbers
题目You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a singl...
分类:其他好文   时间:2014-08-07 12:51:00    阅读次数:188
每天进步一点点——负载均衡之反向代理
转载请说明出处:http://blog.csdn.net/cywosp/article/details/38026809 反向代理(Reverse Proxy)方式是指以代理server来接受internet上的连接请求,然后将请求转发给内部网络上的server,并将从server上得到的结果返回....
分类:其他好文   时间:2014-08-07 12:11:50    阅读次数:216
[LeetCode 题解]: Reverse Nodes in K-Groups
Given a linked list, reverse the nodes of a linked listkat a time and return its modified list.If the number of nodes is not a multiple ofkthen left-o...
分类:其他好文   时间:2014-08-07 00:37:17    阅读次数:187
LeetCode "Reverse Nodes in k-Group"
Another list manipulation problem.class Solution {public: ListNode *reverseKGroup(ListNode *head, int k) { if (!head) return head; if...
分类:其他好文   时间:2014-08-06 06:14:10    阅读次数:232
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