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【POJ1113】Wall(凸包)
【题目】 Description Once upon a time there was a greedy King who ordered his chief Architect to build a wall around the King's castle. The King was so gr ...
分类:其他好文   时间:2016-04-28 20:13:06    阅读次数:285
C++使用Sqlite3,使用CppSQLite3的封装
使用CppSQLite3后操作Sqlite3更加方便 CppSQLite3.h//////////////////////////////////////////////////////////////////////////////// // CppSQLite3 - A C++ wrapper around the SQLite3 embedded database library. // /...
分类:数据库   时间:2016-04-26 19:52:29    阅读次数:189
Leetcode题目:Symmetric Tree
题目: Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: But the ...
分类:其他好文   时间:2016-04-24 06:10:26    阅读次数:162
Turn the corner
Problem Description Mr. West bought a new car! So he is travelling around the city.One day he comes to a vertical corner. The street he is currently i ...
分类:其他好文   时间:2016-04-23 11:51:06    阅读次数:233
Visual Studio Error
Visual Studio Error Debug Error 错误类型 #0表示调用约定错误 可以考虑在指针前面加上_stdcall。Dll库更新了,exe未更新也会报此错误。 #2表示栈溢出 -S是Stack around the variable … was corrupted的缩写 把12个 ...
分类:其他好文   时间:2016-04-20 21:36:53    阅读次数:651
POJ 1041问题描述
Description Little Johnny has got a new car. He decided to drive around the town to visit his friends. Johnny wanted to visit all his friends, but the ...
分类:其他好文   时间:2016-04-20 20:09:00    阅读次数:169
101. Symmetric Tree -- 判断树结构是否对称
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: But the fol ...
分类:其他好文   时间:2016-04-20 13:08:39    阅读次数:164
Spring.Net的AOP的通知
一、拦截环绕通知(around advice):Spring.NET中最基本的通知类型是拦截环绕通知(interception around advice),即方法拦截器。拦截环绕通知继承IMethodInterceptor接口。注意其中IMethodInvocation.Proceed()方法的调 ...
分类:编程语言   时间:2016-04-20 01:59:06    阅读次数:246
Jersey(1.19.1) - Ease of use and reusing JAX-RS artifacts
Since a resource is represented as a Java type it makes it easy to configure, pass around and inject in ways that is not so intuitive or possible with ...
分类:其他好文   时间:2016-04-17 14:44:25    阅读次数:166
Gated Recurrent Unit (GRU)公式简介
update gate $z$: defines how much of the previous memory to keep around. \[z = \sigma (x_t U^z + s_{t-1} W^z )\] reset gate $r$: \[r = \sigma(x_t U^r ...
分类:其他好文   时间:2016-04-14 22:24:33    阅读次数:1899
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