码迷,mamicode.com
首页 >  
搜索关键字:reverse polish notat    ( 5115个结果
LeetCode OJ——练习笔记(1)Evaluate Reverse Polish Notation
院招终于开始了,然后期待与兴奋过后却是面临着笔试一次又一次的失败,然后开始留意到LeetCode。也想自己去体验一下诸多大牛通向无限coding路上都攻克过的一关。话不多说,贴出原题:Evaluate the value of an arithmetic expression inReverse P...
分类:其他好文   时间:2014-07-03 22:01:50    阅读次数:202
LeetCode——Reverse Words in a String
Given an input string, reverse the string word by word.For example,Given s = "the sky is blue",return "blue is sky the".Clarification:What constitutes...
分类:其他好文   时间:2014-07-03 20:45:35    阅读次数:201
[LeetCode]Reverse Integer
[LeetCode]Reverse Integer...
分类:其他好文   时间:2014-07-03 16:36:33    阅读次数:121
[leetcode] Reverse Linked List II
Reverse a linked list from position m to n. Do it in-place and in one-pass.
分类:其他好文   时间:2014-07-02 20:12:57    阅读次数:182
LeetCode: Reverse Words in a String [151]
【题目】 Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". click to show clarification. Clarification: What constitutes a word? A sequence of non-space characters constitutes a word....
分类:其他好文   时间:2014-07-02 08:34:34    阅读次数:170
LeetCode: Evaluate Reverse Polish Notation [150]
【题目】 Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are +, -, *, /. Each operand may be an integer or another expression. Some examples: ["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9 ["4", "13", "5", "/...
分类:其他好文   时间:2014-07-02 07:43:36    阅读次数:212
PowerDesigner
反向数据库File - Reverse - Database - DBMS - Using a data source改变数据库Database - Change Current -DBMS生成数据脚本Database -Generate Databse
分类:其他好文   时间:2014-07-01 21:20:34    阅读次数:215
[Leetcode]Add Two Numbers
题目 You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it a...
分类:其他好文   时间:2014-07-01 09:11:07    阅读次数:206
ACM-ICPC 2014北京邀请赛 H Happy Reverse [模拟]
题意:给出n个二进制串,可以把其中的一些0和1反转(即0变1,1变0),找出转化后n个串中的最大值和最小值的差值。 分析:思路就是把所有的串和反转的存在一个数组中,然后排序,找最大值和最小值的差,(如果是同一个串反转的就找第二大的和最小的或第二小和最大的中的最大值)。注意假如只有一个串的话结果为0 DEBUG: 这题写了好久 1.第一次用vim,很爽,但是还没熟练 2.忽...
分类:移动开发   时间:2014-06-30 19:19:10    阅读次数:254
LeetCode Reverse Linked List II
class Solution {public: ListNode *reverseBetween(ListNode *head, int m, int n) { if (head == NULL || n 0) { pre = cur; ...
分类:其他好文   时间:2014-06-30 15:36:26    阅读次数:148
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!