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February 14th, 2018 Week 7th Wednesday
Love does not dominate, it culitvates. 爱不是羁绊,而是成就。 Love should not wipe out everything you are, love should not overpower you in a negative way and ma ...
分类:其他好文   时间:2018-03-22 10:57:16    阅读次数:168
February 12th, 2018 Week 7th Monday
One man's fault is another man's lesson. 前车之覆,后车之鉴。 We make mistakes every day, large or small, failures or faux pas. But failure and mistakes still d ...
分类:其他好文   时间:2018-03-20 10:36:55    阅读次数:132
February 10th, 2018 Week 6th Saturday
It is not enough to have a good mind. The main thing is to use it well. 头脑聪明还不够,重要的是好好运用。 From Rene Descartes. My colleagues have always brought me so ...
分类:其他好文   时间:2018-03-18 21:37:43    阅读次数:148
February 6th, 2018 Week 6th Tuesday
To be is to be perceived. 存在即被感知。 How to interpret this quote? Maybe it means that everything in your world doesn't exist if you failed to percept it. ...
分类:其他好文   时间:2018-03-14 23:43:10    阅读次数:205
Java反编译工具
Java反编译工具在Eclipse下可以选择Eclipse-Class-Decompiler插件,他是集成了很多工具,有jd,jad,crf等。Java反编译工具参考链接:Eclipse-Class-Decompilerhttps://www.eclipse.org/community/eclipse_newsletter/2017/february/article8.phpgithub下载地址h
分类:编程语言   时间:2018-03-14 14:57:59    阅读次数:168
What can Reactive Streams offer EE4J?
https://developer.lightbend.com/blog/2018-02-06-reactive-streams-ee4j/index.html By James Roper (@jroper), February 6, 2018 In my current role at Ligh ...
分类:其他好文   时间:2018-03-12 17:04:09    阅读次数:201
February 2nd, 2018 Week 5th Friday
Reputation takes a life time to build and a second to destroy. 树立名声需要一生的努力,而毁掉它只需要一秒。 To be a smart man, I must know to do something good even though ...
分类:其他好文   时间:2018-03-12 00:00:41    阅读次数:165
Months and week
January February March April May June July August September October November December ...
分类:其他好文   时间:2018-02-25 17:29:21    阅读次数:131
CodeChef February Challenge 2018 Broken Clock (三角函数推导 + 矩阵快速幂)
题目链接 Broken Clock 中文题面链接 令$cos(xα) = f(x)$ 根据三角函数变换公式有 $f(x) = \frac{2d}{l} f(x-1) - f(x-2)$ 令$f(x) = \frac{g(x)}{l^{x}}$ ...
分类:其他好文   时间:2018-02-18 18:37:51    阅读次数:219
CodeChef February Challenge 2018 Chef and odd queries (分块 + 主席树)
题目链接 Chef and odd queries 题意 给定$n$个区间和$q$个询问,每个询问给定$m$个点,求这$n$个区间中有多少个包含了$m$个点中的奇数个。 分类操作。 对于$m >$ $\sqrt{n}$的询问直接一个前缀和依次枚举,时间复杂度$O(n)$,因为这样的询问不会超过$\s ...
分类:其他好文   时间:2018-02-17 10:26:54    阅读次数:178
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